python五子棋人机对战代码，绘图，并给出胜利条件

以下是一个简单的人机对战五子棋代码，使用Python实现。该代码使用tkinter库实现绘图，并通过判断连续五个相同颜色的棋子来确定胜利条件。

import tkinter as tk
import random

# 初始化棋盘
board = [[0 for i in range(15)] for j in range(15)]

# 初始化窗口
window = tk.Tk()
window.title('五子棋')
window.geometry('450x500')

# 初始化画布
canvas = tk.Canvas(window, bg='white', width=450, height=450)
canvas.pack()

# 绘制棋盘
for i in range(15):
    canvas.create_line(30, 30+i*30, 420, 30+i*30)
    canvas.create_line(30+i*30, 30, 30+i*30, 420)

# 绘制棋子
def draw_piece(x, y, color):
    if color == 'black':
        canvas.create_oval(x*30+15, y*30+15, x*30+45, y*30+45, fill='black')
    else:
        canvas.create_oval(x*30+15, y*30+15, x*30+45, y*30+45, fill='white')

# 判断胜利条件
def check_win(x, y, color):
    count = 1
    # 横向
    for i in range(x-1, -1, -1):
        if board[i][y] == color:
            count += 1
        else:
            break
    for i in range(x+1, 15):
        if board[i][y] == color:
            count += 1
        else:
            break
    if count >= 5:
        return True
    # 纵向
    count = 1
    for i in range(y-1, -1, -1):
        if board[x][i] == color:
            count += 1
        else:
            break
    for i in range(y+1, 15):
        if board[x][i] == color:
            count += 1
        else:
            break
    if count >= 5:
        return True
    # 斜向
    count = 1
    for i, j in zip(range(x-1, -1, -1), range(y-1, -1, -1)):
        if board[i][j] == color:
            count += 1
        else:
            break
    for i, j in zip(range(x+1, 15), range(y+1, 15)):
        if board[i][j] == color:
            count += 1
        else:
            break
    if count >= 5:
        return True
    # 反斜向
    count = 1
    for i, j in zip(range(x-1, -1, -1), range(y+1, 15)):
        if board[i][j] == color:
            count += 1
        else:
            break
    for i, j in zip(range(x+1, 15), range(y-1, -1, -1)):
        if board[i][j] == color:
            count += 1
        else:
            break
    if count >= 5:
        return True
    return False

# 人机对战
def play(x, y):
    if board[x][y] == 0:
        draw_piece(x, y, 'black')
        board[x][y] = 'black'
        if check_win(x, y, 'black'):
            canvas.create_text(225, 225, text='你赢了！', font=('Arial', 20))
            canvas.unbind('<Button-1>')
            return
        while True:
            i = random.randint(0, 14)
            j = random.randint(0, 14)
            if board[i][j] == 0:
                draw_piece(i, j, 'white')
                board[i][j] = 'white'
                if check_win(i, j, 'white'):
                    canvas.create_text(225, 225, text='电脑赢了！', font=('Arial', 20))
                    canvas.unbind('<Button-1>')
                    return
                break

# 绑定鼠标事件
canvas.bind('<Button-1>', lambda event: play(event.x//30, event.y//30))

# 运行窗口
window.mainloop()

该代码实现了人机对战的五子棋游戏，并通过`check_win()`函数判断胜利条件。当有连续五个相同颜色的棋子时，游戏结束。