复数四则运算法则 假设 z1 = a + bi，z2 = c + di 和：z1 + z2 = (a+c) + (b+d)i 差：z1 - z2 = (a-c) + (b-d)i 积：z1 * z2 = (ac-bd) + (bc + ad)i 商：z1 / z2 = (ac + bd)/(c * c+d * d) + (bc-ad)/(c * c+d * d)i 编程要求 根据提示，在右侧编辑器补充代码，计算并输出两个复数的和、差、积、商运算结果。用java写

import java.util.Scanner;

public class ComplexNumber {
    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);
        System.out.print("请输入第一个复数的实部a和虚部b：");
        double a1 = input.nextDouble();
        double b1 = input.nextDouble();
        System.out.print("请输入第二个复数的实部c和虚部d：");
        double c1 = input.nextDouble();
        double d1 = input.nextDouble();

        // 计算和
        double a2 = a1 + c1;
        double b2 = b1 + d1;
        System.out.println("两个复数的和为：" + a2 + " + " + b2 + "i");

        // 计算差
        double a3 = a1 - c1;
        double b3 = b1 - d1;
        System.out.println("两个复数的差为：" + a3 + " + " + b3 + "i");

        // 计算积
        double a4 = a1 * c1 - b1 * d1;
        double b4 = b1 * c1 + a1 * d1;
        System.out.println("两个复数的积为：" + a4 + " + " + b4 + "i");

        // 计算商
        double a5 = (a1 * c1 + b1 * d1) / (c1 * c1 + d1 * d1);
        double b5 = (b1 * c1 - a1 * d1) / (c1 * c1 + d1 * d1);
        System.out.println("两个复数的商为：" + a5 + " + " + b5 + "i");
    }
}