python使用递归输出九九乘法表
时间: 2024-01-18 11:49:33 浏览: 29
好的,这个问题可以回答。以下是Python代码:
```
def multiply_table(n):
if n == 1:
print("1 * 1 = 1")
return
multiply_table(n-1)
for i in range(1, n+1):
print(f"{i} * {n} = {i*n}")
print("")
multiply_table(9)
```
输出结果:
```
1 * 1 = 1
1 * 2 = 2
2 * 2 = 4
1 * 3 = 3
2 * 3 = 6
3 * 3 = 9
1 * 4 = 4
2 * 4 = 8
3 * 4 = 12
4 * 4 = 16
1 * 5 = 5
2 * 5 = 10
3 * 5 = 15
4 * 5 = 20
5 * 5 = 25
1 * 6 = 6
2 * 6 = 12
3 * 6 = 18
4 * 6 = 24
5 * 6 = 30
6 * 6 = 36
1 * 7 = 7
2 * 7 = 14
3 * 7 = 21
4 * 7 = 28
5 * 7 = 35
6 * 7 = 42
7 * 7 = 49
1 * 8 = 8
2 * 8 = 16
3 * 8 = 24
4 * 8 = 32
5 * 8 = 40
6 * 8 = 48
7 * 8 = 56
8 * 8 = 64
1 * 9 = 9
2 * 9 = 18
3 * 9 = 27
4 * 9 = 36
5 * 9 = 45
6 * 9 = 54
7 * 9 = 63
8 * 9 = 72
9 * 9 = 81
```
笑话:为什么程序员总是把 0 和 1 搞混?因为他们从小就被教育 0 和 1 就可以表示一切!