my_list = [888, 666, 123, -233, 250, 13, 250, -222] last_index = len(my_list) - 1 - my_list[::-1].index(250) print(last_index)
时间: 2024-05-24 11:12:16 浏览: 110
The output of this code would be:
6
Explanation:
- The list "my_list" contains some integers.
- The expression "len(my_list) - 1" gives the index of the last element in the list.
- The expression "my_list[::-1].index(250)" gives the index of the last occurrence of the value 250 in the reversed list. The "[::-1]" syntax is used to reverse the list.
- The variable "last_index" is assigned the value of the index of the last occurrence of 250, counted from the end of the list.
- The value of "last_index" is printed, which is 6. This means that the last occurrence of the value 250 is at index 6 (counting from 0) in the original list.
相关问题
my_list = [888, 666,123,-233,250,13,250,-222 , ]last_index = len(my_list) - 1 - my_list[::-1].index(250)print(last_index)
The output of this code will be:
6
Explanation:
- The list "my_list" contains a sequence of integers.
- The variable "last_index" is initialized to the index of the last element in the list (which is the length of the list minus 1).
- The expression "my_list[::-1]" creates a reversed copy of the list.
- The method "index(250)" is called on the reversed list to find the index of the first occurrence of the integer "250" in the reversed list.
- Since the reversed list is a copy of the original list but in reverse order, the index of the first occurrence of "250" in the reversed list corresponds to the index of the last occurrence of "250" in the original list.
- Finally, the value of "last_index" is updated by subtracting the index of the last occurrence of "250" from the total length minus 1.
- The final result is that "last_index" contains the index of the last occurrence of "250" in the original list.
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