帮我用C写一段四象限划分函数

以下为四象限划分函数的C代码实现：

#include <stdio.h>

void quadrant(int x, int y) {
    if (x > 0 && y > 0) {
        printf("The point (%d, %d) is in the first quadrant.\n", x, y);
    }
    else if (x < 0 && y > 0) {
        printf("The point (%d, %d) is in the second quadrant.\n", x, y);
    }
    else if (x < 0 && y < 0) {
        printf("The point (%d, %d) is in the third quadrant.\n", x, y);
    }
    else if (x > 0 && y < 0) {
        printf("The point (%d, %d) is in the fourth quadrant.\n", x, y);
    }
    else if (x == 0 && y == 0) {
        printf("The point (%d, %d) is at the origin.\n", x, y);
    }
    else if (x == 0 && y != 0) {
        printf("The point (%d, %d) is on the y-axis.\n", x, y);
    }
    else if (x != 0 && y == 0) {
        printf("The point (%d, %d) is on the x-axis.\n", x, y);
    }
}

int main() {
    int x, y;
    printf("Enter the x and y coordinates of a point: ");
    scanf("%d %d", &x, &y);
    quadrant(x, y);
    return 0;
}

该函数接收两个参数 x 和 y，代表一个平面直角坐标系上的点的坐标，然后根据点所在的象限或坐标轴输出对应的信息。如果点位于第一象限，则输出 "The point (x, y) is in the first quadrant."；如果点位于第二象限，则输出 "The point (x, y) is in the second quadrant."，以此类推。如果点位于原点，则输出 "The point (x, y) is at the origin."；如果点在 x 轴或 y 轴上，则输出 "The point (x, y) is on the x-axis/y-axis."