module beep( input wire clk, input wire Buzzer, output reg alarm ); reg [23:0] counter; reg [1:0] tone; always @(posedge clk) begin if (Buzzer) begin if (counter == 0) begin case (tone) 2'b00: alarm <= 1'b0; 2'b01: alarm <= ~alarm; 2'b10: alarm <= 1'b1; 2'b11: alarm <= 1'b0; endcase end counter <= counter + 1; if (counter == 1000000) begin counter <= 0; tone <= tone + 1; end else begin // 当使能信号为低电平时,将蜂鸣器输出置为0 alarm <= 1'b0; counter <= 0; tone <= 2'b00; end end end endmodule 改成低电平触发
时间: 2024-02-14 12:26:03 浏览: 63
你想将蜂鸣器的触发方式改为低电平触发。以下是修改后的代码:
```verilog
module beep(
input wire clk,
input wire Buzzer,
output reg alarm
);
reg [23:0] counter;
reg [1:0] tone;
always @(posedge clk or negedge Buzzer) begin
if (!Buzzer) begin
if (counter == 0) begin
case (tone)
2'b00: alarm <= 1'b0;
2'b01: alarm <= ~alarm;
2'b10: alarm <= 1'b1;
2'b11: alarm <= 1'b0;
endcase
end
counter <= counter + 1;
if (counter == 1000000) begin
counter <= 0;
tone <= tone + 1;
end
else begin
// 当使能信号为高电平时,将蜂鸣器输出置为0
alarm <= 1'b0;
counter <= 0;
tone <= 2'b00;
end
end
endmodule
```
在这个修改后的代码中,我在 `always` 块中添加了 `negedge Buzzer` 条件,以在Buzzer信号的下降沿触发时执行相应的操作。当Buzzer信号为低电平时,蜂鸣器会按照之前的逻辑工作;当Buzzer信号为高电平时,蜂鸣器输出将被强制置为低电平。
请注意,具体的实现可能会因FPGA型号和使用的开发工具而有所不同。你可以根据自己的需求进行适当的修改和扩展。
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