根据代码1“public List<ProjectCountVO> projectCount(String beginTime, String endTime, Integer forceType, String projectId) { // 查询任务列表 List<TaskTask> taskTaskList = this.listStatisticsTask(beginTime, endTime, forceType, projectId); if (CollectionUtil.isEmpty(taskTaskList)) { return Collections.emptyList(); } List<ProjectCountVO> result = new ArrayList<>(); // 将任务按照项目ID分组 Map<String, List<TaskTask>> projectTaskMap = taskTaskList.stream().collect(Collectors.groupingBy(TaskTask::getProjectId)); //查询项目名称 String bspToken = RequestHeaderHolder.getBspToken(); String bspUserId = RequestHeaderHolder.getUserId(); String bspUserEnvId = RequestHeaderHolder.getCompanyId(); String bspUserTenant = RequestHeaderHolder.getCompanyId(); String companyId = RequestHeaderHolder.getCompanyId(); ProjectCondition projectCondition = new ProjectCondition(); projectCondition.setAppId("23031408164321600"); projectCondition.setCompanyId(companyId); projectCondition.setDesignStatusList(Arrays.asList(2,3)); projectCondition.setPageSize(-1); projectCondition.setUserId(bspUserId); List<QueryAllProject> queryAllProject = applicationServicePlatformClientProxy.listUserProject(bspToken, bspUserId, bspUserEnvId, bspUserTenant, projectCondition);”修改代码2“// 遍历项目及对应的任务列表 for (Map.Entry<String, List<TaskTask>> projectTaskEntry : projectTaskMap.entrySet()) { projectId = projectTaskEntry.getKey(); ProjectCountVO projectCountVO = new ProjectCountVO(); projectCountVO.setId(projectId); String projectName = queryAllProject; projectCountVO.setName(projectName); List<TaskTask> taskList = projectTaskEntry.getValue(); projectCountVO.setTaskCount(taskList.size()); Integer problemCount = CollectionUtil.isEmpty(taskList) ? 0 : taskList.stream().collect(Collectors.summingInt(task -> Optional.ofNullable(task.getProblemNum()).orElse(0))); projectCountVO.setProblemCount(problemCount); result.add(projectCountVO); } return result;”，最终能够查到指定“projectname”

代码2中，可以通过遍历项目及对应的任务列表，获取每个项目的ID和对应的任务列表。然后使用项目ID查询项目名称，将项目名称设置到对应的ProjectCountVO对象中。最后，将该对象添加到结果集中返回即可。

因此，可以在代码2中的for循环中，使用以下代码获取项目名称：

String projectName = queryAllProject.stream()
                        .filter(project -> project.getId().equals(projectId))
                        .findFirst()
                        .map(QueryAllProject::getName)
                        .orElse("");
projectCountVO.setName(projectName);

这段代码会在查询所有项目列表中找到与当前循环的项目ID相同的项目，并将该项目的名称设置为当前ProjectCountVO对象的名称。如果没有找到对应的项目，则将名称设置为空字符串。

相关问题

通过接口“applicationServicePlatformClient”在下面代码中调用projectname并打印代码：public List<ProjectCountVO> projectCount(String beginTime, String endTime, Integer forceType, String projectId) { List<TaskTask> taskTaskList = this.listStatisticsTask(beginTime, endTime, forceType, projectId); if(CollectionUtil.isEmpty(taskTaskList)){ return Collections.emptyList(); } List<ProjectCountVO> result = new ArrayList<>(); Map<String, List<TaskTask>> projectTaskMap = taskTaskList.stream().collect(Collectors.groupingBy(TaskTask::getProjectId)); for (Map.Entry<String, List<TaskTask>> projectTaskEntry : projectTaskMap.entrySet()) { projectId = projectTaskEntry.getKey(); ProjectCountVO projectCountVO = new ProjectCountVO(); projectCountVO.setId(projectId); //查询项目名称List<TaskTask> taskList = projectTaskEntry.getValue(); projectCountVO.setTaskCount(taskList.size()); Integer problemCount = CollectionUtil.isEmpty(taskList) ? 0 : taskList.stream().collect(Collectors.summingInt(task-> Optional.ofNullable(task.getProblemNum()).orElse(0))); projectCountVO.setProblemCount(problemCount); result.add(projectCountVO); } return result; }

您可以这样调用projectname并打印代码：

public List<ProjectCountVO> projectCount(String beginTime, String endTime, Integer forceType, String projectId) {
    List<TaskTask> taskTaskList = this.listStatisticsTask(beginTime, endTime, forceType, projectId);
    if(CollectionUtil.isEmpty(taskTaskList)){
        return Collections.emptyList();
    }

    List<ProjectCountVO> result = new ArrayList<>();
    Map<String, List<TaskTask>> projectTaskMap = taskTaskList.stream().collect(Collectors.groupingBy(TaskTask::getProjectId));

    for (Map.Entry<String, List<TaskTask>> projectTaskEntry : projectTaskMap.entrySet()) {
        projectId = projectTaskEntry.getKey();
        ProjectCountVO projectCountVO = new ProjectCountVO();
        projectCountVO.setId(projectId);
        
        // 查询项目名称
        String projectName = applicationServicePlatformClient.getProjectName(projectId);
        projectCountVO.setName(projectName);

        List<TaskTask> taskList = projectTaskEntry.getValue();
        projectCountVO.setTaskCount(taskList.size());
        Integer problemCount = CollectionUtil.isEmpty(taskList) ? 0 : taskList.stream().collect(Collectors.summingInt(task-> Optional.ofNullable(task.getProblemNum()).orElse(0)));
        projectCountVO.setProblemCount(problemCount);
        result.add(projectCountVO);
    }
    System.out.println("projectname: " + projectId);
    return result;
}

在for循环中，我们使用项目ID调用`applicationServicePlatformClient`的`getProjectName`方法，获取项目名称并设置到`ProjectCountVO`对象中。最后，在方法结束前打印`projectId`的值。

检查代码： public List<ProjectCountVO> projectCount(String beginTime, String endTime, Integer forceType, String projectId) { List<TaskTask> taskTaskList = this.listStatisticsTask(beginTime, endTime, forceType, projectId); if(CollectionUtil.isEmpty(taskTaskList)){ return Collections.emptyList(); } List<ProjectCountVO> result = new ArrayList<>(); Map<String, List<TaskTask>> projectTaskMap = taskTaskList.stream().collect(Collectors.groupingBy(TaskTask::getProjectId)); for (Map.Entry<String, List<TaskTask>> projectTaskEntry : projectTaskMap.entrySet()) { projectId = projectTaskEntry.getKey(); ProjectCountVO projectCountVO = new ProjectCountVO(); projectCountVO.setId(projectId); ProjectCondition projectCondition = new ProjectCondition(); projectCondition.setProjectName(projectId); //查询项目名称 String projectName = applicationServicePlatformClient.listUserProject(projectCondition.getProjectName(),); projectCountVO.setName(projectName); List<TaskTask> taskList = projectTaskEntry.getValue(); projectCountVO.setTaskCount(taskList.size()); Integer problemCount = CollectionUtil.isEmpty(taskList) ? 0 : taskList.stream().collect(Collectors.summingInt(task-> Optional.ofNullable(task.getProblemNum()).orElse(0))); projectCountVO.setProblemCount(problemCount); result.add(projectCountVO); } return result; }

代码看起来没有明显的问题，但是建议在使用 Optional.ofNullable() 方法时，尽量不要使用 orElse() 方法，而是使用 orElseGet() 方法。这是因为 orElse() 方法会在 Optional 对象为空时无论如何都会执行，而 orElseGet() 方法只有在 Optional 对象为空时才会执行，可以提高一定的性能。修改后的代码如下：

Integer problemCount = CollectionUtil.isEmpty(taskList) ? 0 : taskList.stream().collect(Collectors.summingInt(task -> Optional.ofNullable(task.getProblemNum()).orElseGet(() -> 0)));