用c语言写一个五子棋人机对战程序

好的，下面是一个简单的五子棋人机对战程序的C语言实现：

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

#define ROW 15
#define COL 15

char board[ROW][COL] = {' '}; // 棋盘
char human = 'X'; // 玩家执子
char computer = 'O'; // AI执子

// 打印棋盘
void print_board() {
    printf(" ");
    for (int i = 0; i < COL; i++) {
        printf("%2d", i + 1);
    }
    printf("\n");
    for (int i = 0; i < ROW; i++) {
        printf("%2d", i + 1);
        for (int j = 0; j < COL; j++) {
            printf("%2c", board[i][j]);
        }
        printf("\n");
    }
}

// 判断是否胜利
int is_win(char c) {
    // 判断行
    for (int i = 0; i < ROW; i++) {
        for (int j = 0; j < COL - 4; j++) {
            if (board[i][j] == c && board[i][j + 1] == c && board[i][j + 2] == c && board[i][j + 3] == c && board[i][j + 4] == c) {
                return 1;
            }
        }
    }
    // 判断列
    for (int i = 0; i < ROW - 4; i++) {
        for (int j = 0; j < COL; j++) {
            if (board[i][j] == c && board[i + 1][j] == c && board[i + 2][j] == c && board[i + 3][j] == c && board[i + 4][j] == c) {
                return 1;
            }
        }
    }
    // 判断正斜线
    for (int i = 0; i < ROW - 4; i++) {
        for (int j = 0; j < COL - 4; j++) {
            if (board[i][j] == c && board[i + 1][j + 1] == c && board[i + 2][j + 2] == c && board[i + 3][j + 3] == c && board[i + 4][j + 4] == c) {
                return 1;
            }
        }
    }
    // 判断反斜线
    for (int i = 0; i < ROW - 4; i++) {
        for (int j = 4; j < COL; j++) {
            if (board[i][j] == c && board[i + 1][j - 1] == c && board[i + 2][j - 2] == c && board[i + 3][j - 3] == c && board[i + 4][j - 4] == c) {
                return 1;
            }
        }
    }
    return 0;
}

// AI下棋
void computer_move() {
    int x, y;
    srand((unsigned int) time(NULL));
    do {
        x = rand() % ROW;
        y = rand() % COL;
    } while (board[x][y] != ' ');
    board[x][y] = computer;
    printf("AI下了(%d, %d)\n", x + 1, y + 1);
}

// 玩家下棋
void human_move() {
    int x, y;
    printf("请输入你的落子位置(x y): ");
    scanf("%d %d", &x, &y);
    while (x < 1 || x > ROW || y < 1 || y > COL || board[x - 1][y - 1] != ' ') {
        printf("无效位置，请重新输入(x y): ");
        scanf("%d %d", &x, &y);
    }
    board[x - 1][y - 1] = human;
}

int main() {
    printf("欢迎来到五子棋人机对战游戏！\n");
    printf("玩家执子：X, AI执子：O\n");
    print_board();
    while (1) {
        human_move();
        print_board();
        if (is_win(human)) {
            printf("你赢了！\n");
            break;
        }
        computer_move();
        print_board();
        if (is_win(computer)) {
            printf("AI赢了！\n");
            break;
        }
    }
    return 0;
}

这个程序实现了一个简单的五子棋人机对战，玩家执黑子，AI执白子。玩家通过输入坐标来下棋，AI则随机选择一个空位下棋。程序使用了一个双重循环来判断是否胜利，分别判断行、列、正斜线和反斜线。如果有五个相同的棋子相连，则判断为胜利。