帮我指出这段代码的错误并修改它,如果代码没错请简化:for j in range(5): num = input("请输入密码(8~10位):") a,b,c,x = 0,0,0,0 for i in num: print(i) if i in {"a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"}: a = 1 elif i in {"A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"}: b = 2 elif i in {"1","2","3","4","5","6","7","8","9","0"}: c = 3 else: x = 1 print(a,b,c,x) if a ==1 and b == 2 and c == 3: continue elif x == 1: print("密码要包含大写,小写和数字!!!") break if len(num) < 8: print("密码太短") elif len(num) > 10: print("密码太长") else: print("密码符合") break
时间: 2023-08-15 18:08:34 浏览: 157
PYTHON学习教程:循环代码知识点讲解(for...in、list、tuple元素迭代练习).docx
这段代码没有明显的错误,但可以进行简化和优化。以下是修改后的代码:
```python
while True:
num = input("请输入密码(8~10位):")
if not (8 <= len(num) <= 10):
print("密码长度不符合要求!")
continue
a, b, c = False, False, False
for i in num:
if i.islower():
a = True
elif i.isupper():
b = True
elif i.isdigit():
c = True
if a and b and c:
print("密码符合要求!")
break
else:
print("密码要包含大写字母、小写字母和数字!")
```
这里使用了 while 循环,只有当密码符合要求时才会退出循环。同时使用了一个布尔类型的变量来判断密码是否包含了大写字母、小写字母和数字。这样做代码更简洁,也更易读。
阅读全文