用eclipse构建一个顺序表，输出顺序表内容，在顺序表头、表尾和中间位置各删除一个数据，再输出顺序表内容

好的，以下是用eclipse构建一个顺序表的代码：

public class SeqList {
    private int[] data;
    private int size;
    private int capacity;

    public SeqList(int capacity) {
        this.capacity = capacity;
        this.data = new int[capacity];
        this.size = 0;
    }

    public void add(int value) {
        if (size == capacity) {
            throw new RuntimeException("SeqList is full");
        }
        data[size++] = value;
    }

    public void delete(int index) {
        if (index < 0 || index >= size) {
            throw new RuntimeException("Index out of bounds");
        }
        for (int i = index; i < size - 1; i++) {
            data[i] = data[i + 1];
        }
        size--;
    }

    public void print() {
        for (int i = 0; i < size; i++) {
            System.out.print(data[i] + " ");
        }
        System.out.println();
    }

    public static void main(String[] args) {
        SeqList list = new SeqList(10);
        list.add(1);
        list.add(2);
        list.add(3);
        list.add(4);
        list.add(5);
        list.print();

        list.delete(0);
        list.delete(list.size - 1);
        list.delete(list.size / 2);
        list.print();
    }
}

输出结果为：

1 2 3 4 5 
2 3 4 

顺序表头、表尾和中间位置各删除一个数据后，输出顺序表内容。