c语言代码实现对于大于1的自然数N,可以拆分成若干个大于等于1的自然数之和。 Input 一个大于1的自然数N 1 Output 所有的拆分情况.按由大到小的顺序排列。 Sample Input 6 Sample Output 6=6 6=5+1 6=4+2 6=4+1+1 6=3+3 6=3+2+1 6=3+1+1+1 6=2+2+2 6=2+2+1+1 6=2+1+1+1+1 6=1+1+1+1+1+1
时间: 2023-10-30 13:07:14 浏览: 74
好的,以下是C语言的实现:
```c
#include <stdio.h>
#include <stdlib.h>
// 分割n的所有情况
void split_num(int n, int** res, int* returnSize, int** returnColumnSizes) {
if (n == 1) {
*returnSize = 1;
*res = (int*)malloc(sizeof(int));
(*res)[0] = 1;
*returnColumnSizes = (int*)malloc(sizeof(int));
(*returnColumnSizes)[0] = 1;
} else {
int max_size = n * n; // 最多可能有n个n相加
*res = (int*)malloc(sizeof(int) * max_size);
*returnColumnSizes = (int*)malloc(sizeof(int) * max_size);
int idx = 0;
for (int i = 1; i < n; i++) {
int* sub_res;
int sub_size;
int* sub_column_sizes;
split_num(i, &sub_res, &sub_size, &sub_column_sizes);
for (int j = 0; j < sub_size; j++) {
int sub_length = sub_column_sizes[j];
int* sub_split = (int*)malloc(sizeof(int) * sub_length);
for (int k = 0; k < sub_length; k++) {
sub_split[k] = sub_res[j * sub_length + k];
}
sub_split[sub_length] = n - i;
int col_size = sub_length + 1;
(*res)[idx] = sub_length + 1;
(*returnColumnSizes)[idx] = col_size;
idx++;
for (int k = 0; k < sub_length + 1; k++) {
(*res)[idx] = sub_split[k];
idx++;
}
free(sub_split);
}
free(sub_res);
free(sub_column_sizes);
}
// 最后加上n本身
(*res)[idx] = 1;
(*returnColumnSizes)[idx] = 1;
idx++;
(*res)[idx] = n;
idx++;
*returnSize = idx;
}
}
void print_split(int n, int* res, int size, int* column_sizes) {
for (int i = 0; i < size; i++) {
printf("%d=", n);
for (int j = 0; j < column_sizes[i] - 1; j++) {
printf("%d+", res[i * (n + 1) + j]);
}
printf("%d\n", res[i * (n + 1) + column_sizes[i] - 1]);
}
}
int main() {
int n;
scanf("%d", &n);
int* res;
int size;
int* column_sizes;
split_num(n, &res, &size, &column_sizes);
// 按照由大到小的顺序排列
for (int i = 0; i < size - 1; i++) {
for (int j = i + 1; j < size; j++) {
int idx_i = i * (n + 1);
int idx_j = j * (n + 1);
int sum_i = 0;
int sum_j = 0;
for (int k = 0; k < column_sizes[i]; k++) {
sum_i += res[idx_i + k];
}
for (int k = 0; k < column_sizes[j]; k++) {
sum_j += res[idx_j + k];
}
if (sum_i < sum_j) {
int tmp_size = column_sizes[i];
column_sizes[i] = column_sizes[j];
column_sizes[j] = tmp_size;
for (int k = 0; k < tmp_size; k++) {
int tmp = res[idx_i + k];
res[idx_i + k] = res[idx_j + k];
res[idx_j + k] = tmp;
}
}
}
}
print_split(n, res, size, column_sizes);
free(res);
free(column_sizes);
return 0;
}
```
希望这个代码可以解决你的问题。如果你有其他问题,欢迎随时提出。
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