用C++求解Some number of people (this number is even) have stood in a circle. The people stand in the circle evenly. They are numbered clockwise starting from a person with the number 11. Each person is looking through the circle's center at the opposite person.You don't know the exact number of people standing in the circle (but this number is even, no doubt). It is known that the person with the number ais looking at the person with the number b (and vice versa, of course). What is the number associated with a person being looked at by the person with the number c? If, for the specified a, b, and c, no such circle exists, output -1.

这道题可以使用数学方法来解决。首先，我们可以将每个人看作圆周上的一个点，并将他们按顺序排列。由于每个人都在看着位于他们对面的人，所以可以将他们两两配对，并将他们连成一条线段。如下图所示：

 8-------7
 |       |
 1-------6
 |       |
 2-------5
 |       |
 3-------4

其中，a和b被连成一条线段，c和d被连成一条线段，依此类推。由于人数是偶数，所以每个人都能被配对。现在的问题是，给定a和b，找到c对应的数字。

我们可以从a开始顺时针数数，每数到一个人，就去找他所对应的人。如果在数数的过程中，我们数到了b对应的人，那么我们就得到了整个环的长度。根据这个长度，我们就可以得到每个人对应的数字。

具体来说，我们可以将a的数字设为11，然后顺时针遍历每个人，直到数到b对应的人。假设此时已经数了k个人，那么整个环的长度就是k*2。接下来，我们可以从a开始继续顺时针数数，数到第k/2个人就是c对应的数字。如果k是奇数，那么c对应的数字不存在，输出-1。

下面是C++的代码实现：

相关问题

用C++求解Some number of people (this number is even) have stood in a circle. The people stand in the circle evenly. They are numbered clockwise starting from a person with the number 11. Each person is looking through the circle's center at the opposite person.You don't know the exact number of people standing in the circle (but this number is even, no doubt). It is known that the person with the number ais looking at the person with the number b (and vice versa, of course). What is the number associated with a person being looked at by the person with the number c? If, for the specified a, b, and c, no such circle exists, output -1.

这道题可以使用模拟的方法来解决。首先，我们可以假设人数为n，从11号开始逆时针编号为0, 1, 2, ..., n-1。那么第一个人a和第二个人b的距离为d1 = (b-a+n)%n，因为是逆时针，所以要加上n再取模。同理，第二个人b和第一个人a的距离为d2 = (a-b+n)%n。由题意可知，a和b相对位置对称，所以d1 = d2，即 (b-a+n)%n = (a-b+n)%n，整理得到 b = (2*a)%n。同理可得，c看到的人的编号为d = (2*c)%n，如果d等于b，则输出b，否则输出-1。下面是C++代码实现：

#include <iostream>
using namespace std;

int main() {
    int a, b, c;
    cin >> a >> b >> c;
    int n = 2 * a;
    if (b != (n % b)) {
        cout << "-1" << endl;
    } else {
        int d = 2 * c % n;
        if (d == b) {
            cout << b << endl;
        } else {
            cout << "-1" << endl;
        }
    }
    return 0;
}

The largest animal ever to have lived on Earth is the dinosaur Argentinesaurus, a hulking 70－ton的英文全文

The largest animal ever to have lived on Earth is the dinosaur Argentinosaurus, a hulking 70-ton behemoth that roamed the Earth during the Late Cretaceous period, approximately 90 million years ago. This massive dinosaur was around 100 feet long and stood as tall as a four-story building, making it one of the largest land animals in history.

Argentinosaurus was a sauropod, a group of long-necked, herbivorous dinosaurs that were characterized by their massive size and distinctive body shape. These creatures had thick, columnar legs, long necks, and small heads, and were able to consume vast amounts of vegetation in order to fuel their massive bodies.

Despite its impressive size, Argentinosaurus was not the longest dinosaur ever discovered. That title goes to the slightly smaller Seismosaurus, which was estimated to be around 150 feet long. However, Argentinosaurus remains the largest known land animal in terms of overall mass, and its discovery has shed new light on the incredible diversity of life that once existed on our planet.