could the call function in makefile call two macros simutaneously?

Yes, the `call` function in Makefile can be used to call multiple macros simultaneously. To do this, you can use the `$(eval ...)` function to evaluate a sequence of multiple macro invocations as a single unit.

Here is an example that demonstrates how to use `call` to invoke two macros simultaneously:

define macro1
    @echo "This is macro1"
endef

define macro2
    @echo "This is macro2"
endef

define call_both_macros
    $(eval $(call macro1))
    $(eval $(call macro2))
endef

all:
    $(call call_both_macros)

In this example, we've defined two macros `macro1` and `macro2`, and then defined another macro called `call_both_macros` that calls both `macro1` and `macro2` using the `call` function and the `$(eval ...)` function.

When we run `make`, the `all` target is executed, which invokes `call_both_macros`. This, in turn, invokes `macro1` and `macro2`, and the output will be:

This is macro1
This is macro2

So, the `call` function can indeed be used to call multiple macros simultaneously in Makefile.