for(int i=0;i<31;i++) for(int j=0;j<31;j++) { switch(_MAP[i][j]) { case 1://画障礙物 painter.setBrush(QBrush(Qt::gray,Qt::SolidPattern)); painter.drawRect(QRect(i*25+200-(nodeSpacing-nodeSize)/2,(j+1)*25+50-(nodeSpacing-nodeSize)/2,25,25)); break; case 0://画地圖 painter.setBrush(QBrush(QColor(66, 139, 230),Qt::SolidPattern)); painter.drawRect(QRect((i*25+200),(j+1)*25+50,nodeSize,nodeSize)); break; case 2://路線 painter.setBrush(QBrush(Qt::yellow,Qt::SolidPattern)); painter.drawRect(QRect(i*25+200,(j+1)*25+50,nodeSize,nodeSize)); break; case 3://agv painter.drawPixmap(i*25+200-(nodeSpacing-nodeSize)/2,(j+1)*25+50-(nodeSpacing-nodeSize)/2,25,25,QPixmap(":/new/prefix1/agv1.png").scaled(25,25)); case 5://agv模擬直綫路綫 painter.setBrush(QBrush(QColor(66, 139, 230),Qt::SolidPattern)); painter.drawRect(QRect((i*25+200),(j+1)*25+50,nodeSize,nodeSize));，添加代碼，在map值為5的之間繪製直綫

你的代码中，当_MAP[i][j]的值为5时，会绘制一个蓝色的矩形，但是并没有绘制直线。如果你想要在5之间绘制直线，可以添加以下代码：

case 5: // agv模拟直线路线
    painter.setPen(QPen(QColor(255, 0, 0), 3, Qt::SolidLine)); // 设置画笔颜色、粗细和样式
    painter.drawLine(QPointF(i*25+200+nodeSize/2, (j+1)*25+50+nodeSize/2), QPointF((i+1)*25+200-nodeSize/2, (j+1)*25+50+nodeSize/2)); // 绘制直线
    painter.setBrush(QBrush(QColor(66, 139, 230),Qt::SolidPattern)); // 恢复原来的画刷
    painter.drawRect(QRect((i*25+200),(j+1)*25+50,nodeSize,nodeSize)); // 绘制蓝色矩形
    break;

这段代码中，我设置了一个红色的画笔，使用`QPainter::drawLine()`方法在当前格子的中心绘制了一条水平直线，然后又恢复了原来的画刷，并绘制了蓝色的矩形。你可以根据需要修改画笔的颜色、粗细和样式。

相关问题

#include<stdio.h> int booth[401],t[401][401],dp[401]; int main() { int n; scanf("%d",&n); for(int i=0;i<n;i++) scanf("%d",&booth[i]); for(int i=0;i<n;i++) for(int j=0;j<n;j++) scanf("%d",&t[i][j]); for(int i=0;i<n;i++) if(t[0][i]<=booth[i]) dp[i]=1; int flag=1; while(flag) { flag=0; for(int i=0;i<n;i++) { for(int j=0;j<n;j++) { if(t[i][j]<=(booth[j]-booth[i])&&dp[j]<=dp[i]&&i!=j) { dp[j]=dp[i]+1; flag=1; } } } } int ans=0; for(int i=0;i<n;i++) if(ans<dp[i]) ans=dp[i]; printf("%d",ans); return 0; }转换为c++代码

以下是将给定的 C 代码转换为 C++ 代码后的结果：

#include <iostream>
using namespace std;

int booth[401], t[401][401], dp[401];

int main() {
    int n;
    cin >> n;
    for (int i = 0; i < n; i++)
        cin >> booth[i];
    for (int i = 0; i < n; i++)
        for (int j = 0; j < n; j++)
            cin >> t[i][j];
    for (int i = 0; i < n; i++)
        if (t[0][i] <= booth[i])
            dp[i] = 1;
    int flag = 1;
    while (flag) {
        flag = 0;
        for (int i = 0; i < n; i++) {
            for (int j = 0; j < n; j++) {
                if (t[i][j] <= (booth[j] - booth[i]) && dp[j] <= dp[i] && i != j) {
                    dp[j] = dp[i] + 1;
                    flag = 1;
                }
            }
        }
    }
    int ans = 0;
    for (int i = 0; i < n; i++)
        if (ans < dp[i])
            ans = dp[i];
    cout << ans << endl;
    return 0;
}

#include <iostream> #include <vector> int main() { int n, x; std::cin >> n >> x; std::vector<std::vector<int>> matrix(n, std::vector<int>(n)); // 读取矩阵元素 for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { std::cin >> matrix[i][j]; } } // 更新主对角线元素 for (int i = 0; i < n; i++) { matrix[i][i] += x; } // 更新次对角线元素 for (int i = 0; i < n; i++) { matrix[i][n - 1 - i] += x; } // 输出矩阵 for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { std::cout << matrix[i][j] << " "; } std::cout << std::endl; } return 0; } 把这段代码改成用二维数组实现

Certainly! Here's the modified code using a two-dimensional array:

#include <iostream>

int main() {
    int n, x;
    std::cin >> n >> x;

    int matrix[n][n];

    // 读取矩阵元素
    for (int i = 0; i < n; i++) {
        for (int j = 0; j < n; j++) {
            std::cin >> matrix[i][j];
        }
    }

    // 更新主对角线元素
    for (int i = 0; i < n; i++) {
        matrix[i][i] += x;
    }

    // 更新次对角线元素
    for (int i = 0; i < n; i++) {
        matrix[i][n - 1 - i] += x;
    }

    // 输出矩阵
    for (int i = 0; i < n; i++) {
        for (int j = 0; j < n; j++) {
            std::cout << matrix[i][j] << " ";
        }
        std::cout << std::endl;
    }

    return 0;
}

Please note that in this modified version, a two-dimensional array `matrix` is used instead of a vector.