Given a list of numbers, write a Python program to remove multiple odds elements from a list.
时间: 2024-10-16 10:16:29 浏览: 3
当然可以。在Python中,你可以通过列表推导式和条件判断来实现这个功能。这里是一个简单的例子,它遍历列表中的每个元素,如果元素是偶数,则保留;如果是奇数,并且列表中已经有另一个奇数,就删除它。以下是代码:
```python
def remove_multiple_odds(numbers):
odds_count = {num: numbers.count(num) for num in numbers if num % 2 != 0} # 统计每个奇数出现的次数
result = [num for num in numbers if (num % 2 == 0 or (num % 2 != 0 and odds_count[num] < 2))] # 只保留单个或偶数的奇数
return result
# 示例
numbers_list = [1, 2, 3, 4, 5, 6, 7, 7, 8, 9]
new_list = remove_multiple_odds(numbers_list)
print("原列表:", numbers_list)
print("新列表(去除多于一个的奇数):", new_list)
相关问题
python中有一个items的列表 需要将下列列表中的shuju替换成touzhu https://odds.500.com/fenxi/shuju-1070052.shtml https://odds.500.com/fenxi/shuju-1043590.shtml 要求结果是这样: https://odds.500.com/fenxi/touzhu-1070052.shtml https://odds.500.com/fenxi/touzhu-1043590.shtml怎么做
可以使用Python中的replace()方法来实现这个需求:items = [https://odds.500.com/fenxi/shuju-1070052.shtml, https://odds.500.com/fenxi/shuju-1043590.shtml] new_items = [item.replace('shuju', 'touzhu') for item in items] 最后的结果就是:new_items = [https://odds.500.com/fenxi/touzhu-1070052.shtml, https://odds.500.com/fenxi/touzhu-1043590.shtml]
python中有一个items的列表 需要将下列列表中的shuju替换成touzhu然后保存到new_items https://odds.500.com/fenxi/shuju-1070052.shtml https://odds.500.com/fenxi/shuju-1043590.shtml 要求结果是这样: https://odds.500.com/fenxi/touzhu-1070052.shtml https://odds.500.com/fenxi/touzhu-1043590.shtml
下面是实现该需求的代码:
```
items = ['https://odds.500.com/fenxi/shuju-1070052.shtml', 'https://odds.500.com/fenxi/shuju-1043590.shtml']
new_items = []
for item in items:
new_item = item.replace('shuju', 'touzhu')
new_items.append(new_item)
print(new_items)
```
输出结果为:
```
['https://odds.500.com/fenxi/touzhu-1070052.shtml', 'https://odds.500.com/fenxi/touzhu-1043590.shtml']
```
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