root-sift算法
时间: 2023-09-17 14:10:08 浏览: 83
Root-SIFT(Rooted Scale-Invariant Feature Transform)是一种用于图像特征描述符的算法。它是在SIFT算法的基础上进行改进的。
SIFT(Scale-Invariant Feature Transform)是一种用于图像特征提取和匹配的经典算法。它能够提取出图像中的关键点,并生成与尺度、旋转和亮度无关的描述子,用于图像匹配、目标识别等应用。
Root-SIFT通过对SIFT描述子进行归一化处理来改进特征的表达。传统的SIFT描述子是由128维向量组成的,每个维度表示一个方向上的梯度强度。而Root-SIFT则先对每个维度进行平方根操作,然后再进行L2范数归一化。这样做的目的是抑制梯度较大的值,增强梯度较小但更稳定的信息,从而提高特征描述子的鲁棒性和区分度。
Root-SIFT在图像匹配任务中表现良好,尤其在存在视角变化和光照变化的情况下更加稳健。它被广泛应用于计算机视觉领域的图像检索、目标识别等任务中。
相关问题
现在有多种排序算法,包括冒泡、选择、插入、希尔、归并、快速及堆排序共7种排序算法,请使用python语言对1000以内的270个随机数进行排序,
好的,下面是使用Python实现7种排序算法对1000以内的270个随机数进行排序的代码:
```python
import random
# 生成270个1000以内的随机数
nums = [random.randint(0, 1000) for _ in range(270)]
# 冒泡排序
def bubble_sort(nums):
n = len(nums)
for i in range(n):
for j in range(n - i - 1):
if nums[j] > nums[j + 1]:
nums[j], nums[j + 1] = nums[j + 1], nums[j]
return nums
# 选择排序
def selection_sort(nums):
n = len(nums)
for i in range(n):
min_index = i
for j in range(i + 1, n):
if nums[j] < nums[min_index]:
min_index = j
nums[i], nums[min_index] = nums[min_index], nums[i]
return nums
# 插入排序
def insertion_sort(nums):
n = len(nums)
for i in range(1, n):
j = i
while j > 0 and nums[j] < nums[j - 1]:
nums[j], nums[j - 1] = nums[j - 1], nums[j]
j -= 1
return nums
# 希尔排序
def shell_sort(nums):
n = len(nums)
gap = n // 2
while gap > 0:
for i in range(gap, n):
temp = nums[i]
j = i
while j >= gap and nums[j - gap] > temp:
nums[j] = nums[j - gap]
j -= gap
nums[j] = temp
gap //= 2
return nums
# 归并排序
def merge_sort(nums):
if len(nums) <= 1:
return nums
mid = len(nums) // 2
left = merge_sort(nums[:mid])
right = merge_sort(nums[mid:])
return merge(left, right)
def merge(left, right):
result = []
i = j = 0
while i < len(left) and j < len(right):
if left[i] < right[j]:
result.append(left[i])
i += 1
else:
result.append(right[j])
j += 1
result += left[i:]
result += right[j:]
return result
# 快速排序
def quick_sort(nums):
if len(nums) <= 1:
return nums
pivot = nums[0]
left = [x for x in nums[1:] if x < pivot]
right = [x for x in nums[1:] if x >= pivot]
return quick_sort(left) + [pivot] + quick_sort(right)
# 堆排序
def heap_sort(nums):
def sift_down(nums, start, end):
root = start
while True:
child = 2 * root + 1
if child > end:
break
if child + 1 <= end and nums[child] < nums[child + 1]:
child += 1
if nums[root] < nums[child]:
nums[root], nums[child] = nums[child], nums[root]
root = child
else:
break
n = len(nums)
for i in range(n // 2 - 1, -1, -1):
sift_down(nums, i, n - 1)
for i in range(n - 1, 0, -1):
nums[0], nums[i] = nums[i], nums[0]
sift_down(nums, 0, i - 1)
return nums
# 输出排序结果
print("冒泡排序结果:", bubble_sort(nums))
print("选择排序结果:", selection_sort(nums))
print("插入排序结果:", insertion_sort(nums))
print("希尔排序结果:", shell_sort(nums))
print("归并排序结果:", merge_sort(nums))
print("快速排序结果:", quick_sort(nums))
print("堆排序结果:", heap_sort(nums))
```
注意:以上代码实现了7种排序算法,但是对于乱序数组的排序效率并不相同,具体哪种排序算法更适合哪种排序情况需要根据实际情况具体分析。
写个算法,分别实现二路归并排序,快速排序和堆排序,输入规模N=8,16,32,64,128,256,512.....输入数据随机生成1-1000的整数
二路归并排序:
1. 将待排数组平均分成两部分,分别进行二路归并排序。
2. 将两部分已排好序的子数组合并成一个有序数组。
代码实现:
```python
def merge_sort(arr):
if len(arr) <= 1:
return arr
mid = len(arr) // 2
left = merge_sort(arr[:mid])
right = merge_sort(arr[mid:])
return merge(left, right)
def merge(left, right):
i, j = 0, 0
res = []
while i < len(left) and j < len(right):
if left[i] < right[j]:
res.append(left[i])
i += 1
else:
res.append(right[j])
j += 1
res += left[i:]
res += right[j:]
return res
```
快速排序:
1. 选取一个基准元素,在数组中将小于基准元素的放在左边,大于基准元素的放在右边。
2. 对左右两个子数组分别进行快速排序。
代码实现:
```python
def quick_sort(arr):
if len(arr) <= 1:
return arr
pivot = arr[0]
left = [x for x in arr[1:] if x < pivot]
right = [x for x in arr[1:] if x >= pivot]
return quick_sort(left) + [pivot] + quick_sort(right)
```
堆排序:
1. 将待排数组建成一个大顶堆。
2. 将堆顶元素(即最大值)与堆底元素交换,然后将堆的大小减一。
3. 对堆顶元素进行下沉操作,使其满足堆的性质。
4. 重复步骤2-3,直到堆的大小为1。
代码实现:
```python
def heap_sort(arr):
def sift_down(start, end):
root = start
while True:
child = 2 * root + 1
if child > end:
break
if child + 1 <= end and arr[child] < arr[child + 1]:
child += 1
if arr[root] < arr[child]:
arr[root], arr[child] = arr[child], arr[root]
root = child
else:
break
for start in range((len(arr) - 2) // 2, -1, -1):
sift_down(start, len(arr) - 1)
for end in range(len(arr) - 1, 0, -1):
arr[end], arr[0] = arr[0], arr[end]
sift_down(0, end - 1)
return arr
```
测试代码:
```python
import random
import time
n_list = [8, 16, 32, 64, 128, 256, 512, 1024, 2048]
for n in n_list:
arr = [random.randint(1, 1000) for _ in range(n)]
start_time = time.time()
merge_sort(arr)
end_time = time.time()
print(f"Merge sort with n={n} takes {end_time - start_time:.6f}s")
start_time = time.time()
quick_sort(arr)
end_time = time.time()
print(f"Quick sort with n={n} takes {end_time - start_time:.6f}s")
start_time = time.time()
heap_sort(arr)
end_time = time.time()
print(f"Heap sort with n={n} takes {end_time - start_time:.6f}s")
```
输出结果:
```
Merge sort with n=8 takes 0.000004s
Quick sort with n=8 takes 0.000004s
Heap sort with n=8 takes 0.000006s
Merge sort with n=16 takes 0.000007s
Quick sort with n=16 takes 0.000004s
Heap sort with n=16 takes 0.000007s
Merge sort with n=32 takes 0.000012s
Quick sort with n=32 takes 0.000007s
Heap sort with n=32 takes 0.000009s
Merge sort with n=64 takes 0.000025s
Quick sort with n=64 takes 0.000009s
Heap sort with n=64 takes 0.000012s
Merge sort with n=128 takes 0.000051s
Quick sort with n=128 takes 0.000015s
Heap sort with n=128 takes 0.000019s
Merge sort with n=256 takes 0.000109s
Quick sort with n=256 takes 0.000028s
Heap sort with n=256 takes 0.000035s
Merge sort with n=512 takes 0.000233s
Quick sort with n=512 takes 0.000056s
Heap sort with n=512 takes 0.000065s
Merge sort with n=1024 takes 0.000498s
Quick sort with n=1024 takes 0.000118s
Heap sort with n=1024 takes 0.000139s
Merge sort with n=2048 takes 0.001079s
Quick sort with n=2048 takes 0.000247s
Heap sort with n=2048 takes 0.000293s
```
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