python编写程序实现人与计算机的猜拳游戏

在Python中编写一个人机猜拳游戏可以使用if-elif-else结构来模拟玩家和电脑的选择，并通过随机数生成来模拟电脑的决策。通常，猜拳游戏有三种选择：“石头”、“剪刀”和“布”，规则是这样的：

- 石头打剪刀，剪刀剪布，布包石头。
- 如果双方出同样的选择，则平局。

下面是一个简单的猜拳游戏实现示例：

import random

def computer_choice():
    choices = ["石头", "剪刀", "布"]
    return random.choice(choices)

def get_player_choice():
    player_choice = input("请输入你的选择（石头、剪刀或布）：")
    while player_choice not in ("石头", "剪刀", "布"):
        player_choice = input("无效的选择，请重新输入：")
    return player_choice

def play_game(player, computer):
    if player == computer:
        print(f"平局！你出了{player}，电脑也出了{computer}")
    elif (player == "石头" and computer == "剪刀") or \
         (player == "剪刀" and computer == "布") or \
         (player == "布" and computer == "石头"):
        print(f"你赢了！你出了{player}，电脑出了{computer}")
    else:
        print(f"电脑赢了！你出了{player}，电脑出了{computer}")

# 主循环
while True:
    player_choice = get_player_choice()
    computer_choice = computer_choice()
    print(f"你出了{player_choice}，电脑出了{computer_choice}")
    play_game(player_choice, computer_choice)
    continue_game = input("还想再来一局吗？(y/n): ")
    if continue_game.lower() != 'y':
        break