Calculate the needed amount of powdered reagents in order to prepare two liters of 1.50 M KOH Please show whole processes

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To calculate the needed amount of powdered reagents in order to prepare two liters of 1.50 M KOH, we need to use the following formula:

Number of moles of solute (n) = Molarity (M) x Volume of solution (V)

First, let's convert the given molarity into moles per liter:

1.50 M KOH = 1.50 moles of KOH per liter of solution

Next, we need to calculate the number of moles of KOH required to prepare two liters of the solution:

n = M x V
n = 1.50 moles/L x 2 L
n = 3.00 moles of KOH

Now we can calculate the mass of KOH we need using its molar mass and the number of moles:

Mass (in grams) = Number of moles (n) x Molar mass (Mw)

The molar mass of KOH is:

Atomic mass of K + Atomic mass of O + Atomic mass of H
39.10 g/mol + 15.99 g/mol + 1.01 g/mol
= 56.10 g/mol

Substituting the values:

Mass = 3.00 moles x 56.10 g/mol
Mass = 168.30 g

Therefore, we need 168.30 g of powdered KOH to prepare two liters of 1.50 M KOH solution.