内外盘指针旋转抽奖js代码
时间: 2024-03-03 12:44:43 浏览: 25
根据提供的引用内容,以下是一个内外盘指针旋转抽奖的JavaScript代码示例:
```javascript
// 获取内外盘指针元素
var innerPointer = document.getElementById("inner-pointer");
var outerPointer = document.getElementById("outer-pointer");
// 监听触摸事件
outerPointer.addEventListener("touchmove", function(event) {
// 获取触摸点的坐标
var touchX = event.touches[0].clientX;
var touchY = event.touches[0].clientY;
// 计算触摸点相对于指针中心的偏移量
var centerX = outerPointer.offsetLeft + outerPointer.offsetWidth / 2;
var centerY = outerPointer.offsetTop + outerPointer.offsetHeight / 2;
var diffX = touchX - centerX;
var diffY = touchY - centerY;
// 计算角度
var angle = Math.atan2(diffY, diffX) * (180 / Math.PI);
angle = angle <= 0 ? (360 + angle) : angle;
// 旋转内外盘指针
innerPointer.style.transform = "rotate(" + angle + "deg)";
outerPointer.style.transform = "rotate(" + angle + "deg)";
});
```
请注意,上述代码仅为示例,具体实现可能需要根据实际情况进行调整。