import tkinter as tk def check_word_concatenation(): s = s_entry.get() wordDict = wordDict_entry.get().split() dp = [False] * (len(s) + 1) dp[0] = True for i in range(1, len(s) + 1): for j in range(i): if dp[j] and s[j:i] in wordDict: dp[i] = True break result_label.config(text=str(dp[-1])) window = tk.Tk() window.title("Word Concatenation") s_label = tk.Label(window, text="输入字符串:") s_label.pack() s_entry = tk.Entry(window) s_entry.pack() wordDict_label = tk.Label(window, text="输入字典:") wordDict_label.pack() wordDict_entry = tk.Entry(window) wordDict_entry.pack() check_button = tk.Button(window, text="判断是否可以拼接", command=check_word_concatenation) check_button.pack() result_label = tk.Label(window, text="") result_label.pack() window.mainloop() 注释
时间: 2024-04-16 21:26:28 浏览: 163
code09_tkinter_login.pyw_python_tkinter_notepad.pyw_
下面是代码的注释说明:
```python
import tkinter as tk
# 定义判断函数
def check_word_concatenation():
# 获取输入框中的字符串和字典值
s = s_entry.get()
wordDict = wordDict_entry.get().split()
# 创建动态规划数组,默认值为False
dp = [False] * (len(s) + 1)
dp[0] = True
# 动态规划遍历字符串和子串
for i in range(1, len(s) + 1):
for j in range(i):
# 如果前面的位置可以拼接成单词,并且当前子串在字典中,则将当前位置置为True
if dp[j] and s[j:i] in wordDict:
dp[i] = True
break
# 在结果标签中显示判断结果
result_label.config(text=str(dp[-1]))
# 创建窗口对象
window = tk.Tk()
window.title("Word Concatenation")
# 创建输入框和标签用于输入字符串和字典
s_label = tk.Label(window, text="输入字符串:")
s_label.pack()
s_entry = tk.Entry(window)
s_entry.pack()
wordDict_label = tk.Label(window, text="输入字典:")
wordDict_label.pack()
wordDict_entry = tk.Entry(window)
wordDict_entry.pack()
# 创建按钮,点击时调用判断函数
check_button = tk.Button(window, text="判断是否可以拼接", command=check_word_concatenation)
check_button.pack()
# 创建结果标签,用于显示判断结果
result_label = tk.Label(window, text="")
result_label.pack()
# 进入窗口的主循环
window.mainloop()
```
这些注释解释了代码的不同部分和功能。你可以根据需要添加或修改注释以提高代码的可读性和可维护性。
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