写一个C语言触碰屏九宫格密码

在C语言中编写一个模拟触碰屏九宫格密码输入功能通常涉及到一些假设，因为C语言本身并不直接支持触摸屏幕操作，这通常是UI框架或操作系统级别的功能。然而，我们可以创建一个伪代码示例，模拟用户在一个二维数组（代表九宫格）上点击，并验证输入的密码是否正确。

#include <stdio.h>

#define PASSWORD_SIZE 3 // 九宫格的大小
#define GRID_WIDTH 3

typedef enum { NOT_CLICKED, CLICKED } CellState;

// 九宫格结构
typedef struct {
    int grid[GRID_WIDTH][GRID_WIDTH];
    CellState state[GRID_WIDTH * GRID_WIDTH];
} Grid;

void display_grid(Grid* grid) {
    for (int i = 0; i < GRID_WIDTH; i++) {
        for (int j = 0; j < GRID_WIDTH; j++) {
            if (grid->state[i * GRID_WIDTH + j] == CLICKED) {
                printf("* ");
            } else {
                printf(" _ ");
            }
        }
        printf("\n");
    }
}

void touch_screen(Grid* grid) {
    int row, col;
    printf("Touch a cell to enter the password: ");
    scanf("%d %d", &row, &col);
    // 简单检查边界和网格范围
    if (row >= 0 && row < GRID_WIDTH && col >= 0 && col < GRID_WIDTH) {
        grid->state[row * GRID_WIDTH + col] = CLICKED;
    }
}

bool is_password_valid(Grid* grid, int expected_password) {
    int sum = 0;
    for (int i = 0; i < GRID_WIDTH * GRID_WIDTH; i++) {
        if (grid->state[i] == CLICKED) {
            sum += grid->grid[i / GRID_WIDTH][i % GRID_WIDTH]; // 按行或列计算和
        }
    }
    return sum == expected_password;
}

int main() {
    Grid grid;
    int expected_password = 45; // 假设密码是1+2+3+6+7+8+9=45
    touch_screen(&grid);

    if (is_password_valid(&grid, expected_password)) {
        printf("Correct! Password accepted.\n");
    } else {
        printf("Incorrect! Try again.\n");
    }

    return 0;
}