std::tuple<std::string, std::string, std::string, std::string>其中4个std::string依次为id、type、info、start_id改为std::variant
时间: 2023-11-16 18:04:16 浏览: 154
将std::tuple<std::string, std::string, std::string, std::string>改为std::variant可以使用以下方式:
```cpp
#include <variant>
#include <string>
using MyVariant = std::variant<std::string, std::string, std::string, std::string>;
int main() {
MyVariant variant;
variant = "id";
variant = "type";
variant = "info";
variant = "start_id";
return 0;
}
```
这样,你就可以使用std::variant来存储id、type、info和start_id这四个std::string类型的值了。
相关问题
std::vector<std::tuple<int32_t, std::string, std::string, std::string>> routerState;取出第二个元素
你可以使用`std::get<>()`函数来取出元组中的特定元素。在这种情况下,你可以使用`std::get<1>()`来获取第二个元素。
以下是一个示例代码:
```cpp
#include <iostream>
#include <vector>
#include <tuple>
#include <string>
int main() {
std::vector<std::tuple<int32_t, std::string, std::string, std::string>> routerState;
// 添加一些元组到routerState
routerState.push_back(std::make_tuple(1, "element1", "element2", "element3"));
routerState.push_back(std::make_tuple(2, "element4", "element5", "element6"));
// 取出第二个元素
std::string secondElement = std::get<1>(routerState[0]);
std::cout << "Second element: " << secondElement << std::endl; // 输出:Second element: element1
return 0;
}
```
std::vector<std::tuple<int32_t, std::string, std::string, std::string>> routerState;取出第一个元素
你可以使用`std::get`函数来取出`std::vector<std::tuple<int32_t, std::string, std::string, std::string>>`中的第一个元素。下面是示例代码:
```cpp
#include <iostream>
#include <vector>
#include <tuple>
int main() {
std::vector<std::tuple<int32_t, std::string, std::string, std::string>> routerState;
// 添加一些元素到routerState
routerState.push_back(std::make_tuple(1, "A", "B", "C"));
routerState.push_back(std::make_tuple(2, "D", "E", "F"));
routerState.push_back(std::make_tuple(3, "G", "H", "I"));
// 取出第一个元素
auto firstElement = std::get<0>(routerState[0]);
std::cout << "First element: " << firstElement << std::endl; // 输出:First element: 1
return 0;
}
```
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