请给出实际的代码,不需要简化
时间: 2024-09-22 11:08:48 浏览: 14
当然,这是一个完整的Python代码片段,用于检查输入的扑克牌数组并找出有效的顺子:
```python
def find_sequences(poker_cards):
poker_cards = [int(card) for card in poker_cards.split()]
def is_valid_sequence(seq):
return all(seq[i] == seq[0] + i for i in range(1, len(seq))) and 2 not in seq and len(seq) >= 5
sequences = []
for i in range(len(poker_cards) - 4):
current_seq = [poker_cards[i]]
if is_valid_sequence(current_seq + [poker_cards[i+1], poker_cards[i+2], poker_cards[i+3]]):
sequences.append(' '.join(map(str, current_seq)))
# 如果当前牌不是最大,还有可能接着寻找更大的顺子
if i + 4 < len(poker_cards) and poker_cards[i + 4] > poker_cards[i]:
current_seq = [poker_cards[i]]
for j in range(i + 4, i + 8): # 只能尝试增加最多3张牌,因为不能再超过5张
if is_valid_sequence(current_seq + [poker_cards[j]]):
sequences.append(' '.join(map(str, current_seq + [poker_cards[j]])))
break
return "\n".join(sequences) if sequences else 'No'
# 示例输入
poker_cards_input = "2 9 J 2 3 4 K A 7 9 A 5 6"
output = find_sequences(poker_cards_input)
print(output)
```
这段代码首先将输入的字符串分割并转换为整数列表,然后定义了一个辅助函数`is_valid_sequence`来判断一个序列是否有效。接下来,它通过嵌套循环和条件判断来查找所有可能的顺子。最后返回结果或输出"No"。