linux简易计算器

以下是一个简单的Linux计算器的实现方法：

#include <stdio.h>
#include <math.h>

int main() {
    char operator;
    double num1, num2, result;

    printf("请输入运算符 (+, -, *, /, %%, ^)：");
    scanf("%c", &operator);

    printf("请输入两个数字：\n");
    scanf("%lf %lf", &num1, &num2);

    switch(operator) {
        case '+':
            result = num1 + num2;
            break;
        case '-':
            result = num1 - num2;
            break;
        case '*':
            result = num1 * num2;
            break;
        case '/':
            result = num1 / num2;
            break;
        case '%':
            result = fmod(num1, num2);
            break;
        case '^':
            result = pow(num1, num2);
            break;
        default:
            printf("错误！运算符无效。");
    }

    printf("结果为：%.2lf", result);
    return 0;
}