gps周内秒转日历c程序

GPS时间通常是以星期几（Sunday = 0）和毫秒数来表示的，其中一周包含86400秒（每天24小时*60分钟*60秒）。如果你需要将GPS周内的秒转换成日期，你可以编写一个简单的C程序来完成这个计算。下面是一个简化的示例：

#include <stdio.h>

// Function to convert GPS seconds to calendar date
void gps_seconds_to_date(long gps_seconds) {
    int days_since_sunday = gps_seconds / (24 * 60 * 60); // Calculate the number of full days
    long milliseconds_in_day = gps_seconds % (24 * 60 * 60);
    
    time_t cal_time = mktime(&(struct tm){
        .tm_year = 1970 - 1, // Since GPS epoch is from Jan 6, 1980
        .tm_mon = days_since_sunday / 30, // Approximate month calculation
        .tm_mday = days_since_sunday % 30 + 1,
        .tm_hour = milliseconds_in_day / 3600,
        .tm_min = (milliseconds_in_day % 3600) / 60,
        .tm_sec = milliseconds_in_day % 60,
        .tm_wday = 0, // Sunday
        .tm_yday = days_since_sunday,
        .tm_isdst = -1 // Not used in this context
    });
    
    printf("Date: %d/%02d/%02d\n", cal_time / (24 * 3600), (cal_time / 3600) % 24, cal_time % 3600 / 60);
}

int main() {
    long gps_seconds_input;
    printf("Enter GPS seconds: ");
    scanf("%ld", &gps_seconds_input);

    gps_seconds_to_date(gps_seconds_input);
    return 0;
}