subroutine language3(n,t,x,y,f) implicit none integer i,n,m real(8), dimension (n):: x,y real(8) t,f,u,v,w m=n-1 do 10 i=3,m if(t.gt.x(i)) goto 10 if(abs(t-x(i-1)).le.abs(t-x(i))) goto 20 10 continue i=n 20 i=i-1 u=(t-x(i ))*(t-x(i+1))/(x(i-1)-x(i ))/(x(i-1)-x(i+1)) v=(t-x(i-1))*(t-x(i+1))/(x(i )-x(i-1))/(x(i )-x(i+1)) w=(t-x(i-1))*(t-x(i ))/(x(i+1)-x(i-1))/(x(i+1)-x(i )) f=u*y(i-1)+v*y(i)+w*y(i+1) return end转换成MATLAB语言并编辑出来
时间: 2023-10-09 10:06:59 浏览: 44
function f = language3(n, t, x, y)
m = n - 1;
i = 3;
while t > x(i)
if abs(t - x(i-1)) <= abs(t - x(i))
i = i - 1;
end
i = i + 1;
end
u = (t - x(i)) * (t - x(i+1)) / (x(i-1) - x(i)) / (x(i-1) - x(i+1));
v = (t - x(i-1)) * (t - x(i+1)) / (x(i) - x(i-1)) / (x(i) - x(i+1));
w = (t - x(i-1)) * (t - x(i)) / (x(i+1) - x(i-1)) / (x(i+1) - x(i));
f = u * y(i-1) + v * y(i) + w * y(i+1);
end
相关问题
MODULE MY_MODULE IMPLICIT NONE INTERFACE _____ !<==BLANK1 MODULE PROCEDURE SI,______ !<==BLANK2 END INTERFACE CONTAINS SUBROUTINE SI(A,B) INTEGER::A,B,T T=A;A=B;B=T END SUBROUTINE SUBROUTINE SC(A,B) CHARACTER(LEN=5)::A,B,T T=A;A=B;B=T END SUBROUTINE END MODULE MY_MODULE PROGRAM EX USE ______ !<==BLANK3 IMPLICIT NONE INTEGER::A=2,B=6 CHARACTER(LEN=5)::C1='ABCDE',C2='12345' CALL SWAP(A,B) CALL SWAP(C1,C2) PRINT *,A,B PRINT *,C1,C2 END
根据代码中的提示,需要填写三个空白处,分别为 BLANK1、BLANK2 和 BLANK3。BLANK1 中应该填写 SUBROUTINE,因为我们要定义一个子程序的接口。BLANK2 中应该填写 SC,因为我们需要在接口中列出可以使用的子程序,而 SC 是其中之一。BLANK3 中应该填写 MY_MODULE,因为我们在程序中使用了 MY_MODULE 中定义的子程序。因此,填写后的代码如下:
```
MODULE MY_MODULE
IMPLICIT NONE
INTERFACE
SUBROUTINE SC(A,B)
CHARACTER(LEN=5)::A,B,T
T=A;A=B;B=T
END SUBROUTINE
MODULE PROCEDURE SI,SC
END INTERFACE
CONTAINS
SUBROUTINE SI(A,B)
INTEGER::A,B,T
T=A;A=B;B=T
END SUBROUTINE
END MODULE MY_MODULE
PROGRAM EX
USE MY_MODULE
IMPLICIT NONE
INTEGER::A=2,B=6
CHARACTER(LEN=5)::C1='ABCDE',C2='12345'
CALL SWAP(A,B)
CALL SWAP(C1,C2)
PRINT *,A,B
PRINT *,C1,C2
END
```
Write a LC-3 subroutine for printing “Hello” for N times. Write a main program to input N from the keyboard, call the subroutine and then output “Hello” for N times.
Here is an example LC-3 subroutine to print "Hello" for N times:
```
; Subroutine to print "Hello" for N times
; Input: R0 = N
; Output: None
PRINT_HELLO AND R1, R1, #0 ; Initialize counter to 0
BRnzp LOOP ; Branch to loop
PRINT_STR TRAP x22 ; Print string
.STRINGZ "Hello\n"
LOOP ADD R1, R1, #1 ; Increment counter
NOT R2, R1 ; R2 = -counter
ADD R2, R2, #1 ; R2 = N - counter
BRz END_LOOP ; Branch to end loop if counter = N
BRnzp PRINT_STR ; Print "Hello"
BRnzp LOOP ; Loop back
END_LOOP RET ; Return from subroutine
```
And here is an example LC-3 main program to input N from the keyboard, call the subroutine, and output "Hello" for N times:
```
.ORIG x3000
; Main program to input N, call subroutine, and output "Hello" for N times
LEA R0, PROMPT ; Print prompt to enter N
PUTS
GETC ; Get character
OUT
IN ; Read character
LD R1, ASCII_ZERO ; Convert character to number
ADD R0, R1, #0
OUT
LOOP ; Call subroutine to print "Hello" for N times
LEA R0, NEWLINE ; Print newline
PUTS
HALT
PROMPT .STRINGZ "Enter N: "
NEWLINE .STRINGZ "\n"
ASCII_ZERO .FILL x0030 ; ASCII code for '0'
.END
```