银行家算法 C语言
时间: 2023-12-01 22:42:10 浏览: 31
银行家算法是一种避免死锁的算法,它通过动态地分配资源来避免进程死锁。下面是一个简单的C语言实现:
```c
#include <stdio.h>
#include <stdbool.h>
// 定义最大进程数和资源数
#define MAX_PROCESS 10
#define MAX_RESOURCE 10
// 定义进程和资源的数量
int num_process, num_resource;
// 定义可用资源和最大需求矩阵
int available[MAX_RESOURCE], max_need[MAX_PROCESS][MAX_RESOURCE];
// 定义已分配和需求矩阵
int allocation[MAX_PROCESS][MAX_RESOURCE], need[MAX_PROCESS][MAX_RESOURCE];
// 定义安全序列
int safe_sequence[MAX_PROCESS];
// 检查进程是否可以分配资源
bool is_safe(int process) {
// 检查进程的需求是否小于等于可用资源
for (int i = 0; i < num_resource; i++) {
if (need[process][i] > available[i]) {
return false;
}
}
return true;
}
// 银行家算法
bool banker_algorithm() {
// 初始化工作
int work[MAX_RESOURCE];
for (int i = 0; i < num_resource; i++) {
work[i] = available[i];
}
bool finish[MAX_PROCESS] = {false};
// 找到一个安全序列
int count = 0;
while (count < num_process) {
bool found = false;
for (int i = 0; i < num_process; i++) {
if (!finish[i] && is_safe(i)) {
// 找到一个可以分配资源的进程
for (int j = 0; j < num_resource; j++) {
work[j] += allocation[i][j];
}
safe_sequence[count++] = i;
finish[i] = true;
found = true;
}
}
if (!found) {
// 没有找到可以分配资源的进程
return false;
}
}
return true;
}
int main() {
// 输入进程和资源的数量
printf("Enter the number of processes: ");
scanf("%d", &num_process);
printf("Enter the number of resources: ");
scanf("%d", &num_resource);
// 输入可用资源和最大需求矩阵
printf("Enter the available resources: ");
for (int i = 0; i < num_resource; i++) {
scanf("%d", &available[i]);
}
printf("Enter the maximum need matrix:\n");
for (int i = 0; i < num_process; i++) {
printf("Process %d: ", i);
for (int j = 0; j < num_resource; j++) {
scanf("%d", &max_need[i][j]);
}
}
// 输入已分配矩阵并计算需求矩阵
printf("Enter the allocation matrix:\n");
for (int i = 0; i < num_process; i++) {
printf("Process %d: ", i);
for (int j = 0; j < num_resource; j++) {
scanf("%d", &allocation[i][j]);
need[i][j] = max_need[i][j] - allocation[i][j];
}
}
// 运行银行家算法
if (banker_algorithm()) {
printf("Safe sequence: "); for (int i = 0; i < num_process; i++) {
printf("%d ", safe_sequence[i]);
}
printf("\n");
} else {
printf("Unsafe state\n");
}
return 0;
}
```