所需用到的核心代码
时间: 2023-09-02 07:07:39 浏览: 23
下面是一个简单的银行家算法的示例代码,主要用于检查系统是否安全,以避免出现死锁:
```c
#include <stdio.h>
int main()
{
int available[10], maximum[10][10], allocation[10][10], need[10][10], safe[10];
int n, m, i, j, k, count = 0, flag = 0;
printf("Enter the number of processes: ");
scanf("%d", &n);
printf("Enter the number of resources: ");
scanf("%d", &m);
printf("Enter the availability of resources: ");
for (i = 0; i < m; i++)
{
scanf("%d", &available[i]);
}
printf("Enter the maximum demand of each process: ");
for (i = 0; i < n; i++)
{
printf("For process %d: ", i + 1);
for (j = 0; j < m; j++)
{
scanf("%d", &maximum[i][j]);
}
}
printf("Enter the allocation for each process: ");
for (i = 0; i < n; i++)
{
printf("For process %d: ", i + 1);
for (j = 0; j < m; j++)
{
scanf("%d", &allocation[i][j]);
}
}
// Calculate the need matrix
for (i = 0; i < n; i++)
{
for (j = 0; j < m; j++)
{
need[i][j] = maximum[i][j] - allocation[i][j];
}
}
// Check if the system is in safe state
while (count < n)
{
flag = 0;
for (i = 0; i < n; i++)
{
if (safe[i] == 0)
{
for (j = 0; j < m; j++)
{
if (need[i][j] > available[j])
{
break;
}
}
if (j == m)
{
for (k = 0; k < m; k++)
{
available[k] += allocation[i][k];
}
safe[i] = 1;
flag = 1;
count++;
}
}
}
if (flag == 0)
{
printf("The system is not in safe state.\n");
return 0;
}
}
printf("The system is in safe state.\n");
return 0;
}
```
这段代码实现了银行家算法的基本功能,包括输入各种资源的数量、进程的最大需求和已分配资源等信息,然后计算出每个进程的需求矩阵,最后检查系统是否处于安全状态。