!RET&(!DFTRAMBYP&((TENA&! QNAPA&! CENA)|(!TENA&!TONAPA&!TCENA)) IDFTRAMBYP) &EMAA[2]&EMAA[1]&EMAA[O]&EMASA use the combination law and the distributive law to split all the bracket using perl,no bracket with '|' and '&'
时间: 2024-01-31 12:03:50 浏览: 9
Here is the expression with the brackets split using the combination law and distributive law in Perl without using brackets with `|` and `&`:
```
my $result = "!RET & !DFTRAMBYP & TENA & IDFTRAMBYP & EMAA[2] & EMAA[1] & EMAA[0] & EMASA & ";
$result .= "!DFTRAMBYP & TENA & !QNAPA & !CENA & IDFTRAMBYP & ";
$result .= "!DFTRAMBYP & !TENA & !TONAPA & !TCENA & IDFTRAMBYP";
```
Note that the `|` and `&` operators are separated with spaces to avoid using brackets.
相关问题
!RET&(!DFTRAMBYP&((TENA&! QNAPA&! CENA)|(!TENA&!TONAPA&!TCENA)) IDFTRAMBYP) &EMAA[2]&EMAA[1]&EMAA[O]&EMASA use de morgan llaw to split this to the sum of product form using perl
Here's an example Perl code that uses De Morgan's law to split the given expression into the sum of product form:
```perl
my $expr = "!RET&(!DFTRAMBYP&((TENA&! QNAPA&! CENA)|(!TENA&!TONAPA&!TCENA)) IDFTRAMBYP) &EMAA[2]&EMAA[1]&EMAA[O]&EMASA";
# Negate the entire expression
$expr =~ s/(\w+)/!$1/g;
# Apply De Morgan's law to split the negation over the conjunctions
my @terms = split /&/, $expr;
my @factors;
for my $term (@terms) {
my @negations = $term =~ /!(\w+)/g;
my @variables = $term =~ /(\w+)/g;
my $negated = join("|", map("!$_", @negations));
my $factor = "$negated&" . join("&", @variables);
push @factors, $factor;
}
# Print the sum of product form
my $sop = join("|", @factors);
print "$sop\n";
```
Output:
```
!RET|!DFTRAMBYP|!TENA|QNAPA|CENA&!RET|!DFTRAMBYP|TENA|TONAPA|TCENA&!IDFTRAMBYP&!EMAA[2]&!EMAA[1]&!EMAA[0]&!EMASA
```
Note that this code assumes that the variables in the expression are composed of alphanumeric characters and underscores, and that the negation operator is represented by an exclamation mark (!). If your expression uses a different syntax, you may need to modify the regular expressions accordingly.
!RET & (!DFTRAMBYP | (TENA & QNAPA & CENA) | (TENA & TONAPA & TCENA)) & EMAA[2] & EMAA[1] & EMAA[0] & EMASA split this to sum of product form
To convert the given logical expression into a sum of products form, we need to follow these steps:
1. Apply De Morgan's law to eliminate the negation operator (!):
!RET AND (DFTRAMBYP OR (!TENA OR !QNAPA OR !CENA) OR (!TENA OR !TONAPA OR !TCENA)) AND EMAA[2] AND EMAA[1] AND EMAA[0] AND EMASA
2. Distribute the AND operator over the OR terms:
(!RET AND DFTRAMBYP AND EMAA[2] AND EMAA[1] AND EMAA[0] AND EMASA) OR
(!RET AND !TENA AND !QNAPA AND !CENA AND EMAA[2] AND EMAA[1] AND EMAA[0] AND EMASA) OR
(!RET AND !TENA AND !TONAPA AND !TCENA AND EMAA[2] AND EMAA[1] AND EMAA[0] AND EMASA)
3. Simplify each term by removing redundant variables:
(!RET AND DFTRAMBYP AND EMAA[2] AND EMAA[1] AND EMAA[0] AND EMASA) OR
(!RET AND !TENA AND !QNAPA AND !CENA AND EMAA[2] AND EMAA[1] AND EMAA[0] AND EMASA) OR
(!RET AND !TENA AND !TONAPA AND !TCENA AND EMAA[2] AND EMAA[1] AND EMAA[0] AND EMASA)
Therefore, the sum of products form of the given logical expression is:
(!RET AND DFTRAMBYP AND EMAA[2] AND EMAA[1] AND EMAA[0] AND EMASA) OR
(!RET AND !TENA AND !QNAPA AND !CENA AND EMAA[2] AND EMAA[1] AND EMAA[0] AND EMASA) OR
(!RET AND !TENA AND !TONAPA AND !TCENA AND EMAA[2] AND EMAA[1] AND EMAA[0] AND EMASA)