SHA256哈希算法verilog
时间: 2023-07-09 10:16:09 浏览: 134
以下是SHA256哈希算法的Verilog实现示例:
```verilog
module SHA256(
input clk,
input [511:0] message,
output [255:0] hash
);
reg [31:0] H[7];
reg [31:0] W[63];
reg [31:0] a,b,c,d,e,f,g,h;
reg [31:0] temp1,temp2;
reg [31:0] S0,S1;
reg [31:0] ch,maj;
assign hash = {H[0],H[1],H[2],H[3],H[4],H[5],H[6]};
initial begin
H[0] = 32'h6a09e667;
H[1] = 32'hbb67ae85;
H[2] = 32'h3c6ef372;
H[3] = 32'ha54ff53a;
H[4] = 32'h510e527f;
H[5] = 32'h9b05688c;
H[6] = 32'h1f83d9ab;
end
always @(posedge clk) begin
// Message schedule
for (int i = 0; i < 16; i = i + 1) begin
W[i] = message[i*32+31:i*32];
end
for (int i = 16; i < 64; i = i + 1) begin
S0 = (W[i-15]>>>7) ^ (W[i-15]>>>18) ^ (W[i-15]>>3);
S1 = (W[i-2]>>>17) ^ (W[i-2]>>>19) ^ (W[i-2]>>10);
W[i] = W[i-16] + S0 + W[i-7] + S1;
end
// Compression
a = H[0]; b = H[1]; c = H[2]; d = H[3];
e = H[4]; f = H[5]; g = H[6]; h = 32'hbe0e27b;
for (int i = 0; i < 64; i = i + 1) begin
S1 = (e>>>6) ^ (e>>>11) ^ (e>>>25);
ch = (e & f) ^ ((~e) & g);
temp1 = h + S1 + ch + K[i] + W[i];
S0 = (a>>>2) ^ (a>>>13) ^ (a>>>22);
maj = (a & b) ^ (a & c) ^ (b & c);
temp2 = S0 + maj;
h = g; g = f; f = e; e = d + temp1; d = c; c = b; b = a; a = temp1 + temp2;
end
// Update hash values
H[0] = H[0] + a; H[1] = H[1] + b; H[2] = H[2] + c; H[3] = H[3] + d;
H[4] = H[4] + e; H[5] = H[5] + f; H[6] = H[6] + g; H[7] = H[7] + h;
end
endmodule
```
上述代码是一个SHA256哈希算法的简单实现,其中包含了消息扩展和压缩两个步骤。在实际应用中,需要进行更复杂的设计以提高安全性和性能。
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