c语言编程实现一元多项式加法运算，以(0,0)作为输入结束。

#include <stdio.h>

#define MAX_TERMS 100

typedef struct {
float coef; // 系数
int exp; // 指数
} Term;

void input_poly(Term poly[]);
void add_poly(const Term poly1[], const Term poly2[], Term result[]);
void print_poly(const Term poly[]);

int main() {
Term poly1[MAX_TERMS], poly2[MAX_TERMS], result[MAX_TERMS];

printf("请输入第一个多项式：\n");
input_poly(poly1);

printf("请输入第二个多项式：\n");
input_poly(poly2);

add_poly(poly1, poly2, result);

printf("两个多项式相加的结果为：\n");
print_poly(result);

return 0;
}

void input_poly(Term poly[]) {
int i = 0;
while (1) {
printf("请输入第%d项的系数和指数：", i + 1);
scanf("%f%d", &poly[i].coef, &poly[i].exp);

if (poly[i].coef == 0 && poly[i].exp == 0) {
break;
}

i++;
}
}

void add_poly(const Term poly1[], const Term poly2[], Term result[]) {
int i = 0, j = 0, k = 0;

while (poly1[i].coef != 0 || poly1[i].exp != 0 || poly2[j].coef != 0 || poly2[j].exp != 0) {
if (poly1[i].exp > poly2[j].exp) {
result[k] = poly1[i];
i++;
} else if (poly1[i].exp < poly2[j].exp) {
result[k] = poly2[j];
j++;
} else {
result[k].coef = poly1[i].coef + poly2[j].coef;
result[k].exp = poly1[i].exp;

i++;
j++;
}

k++;
}

result[k].coef = 0;
result[k].exp = 0;
}

void print_poly(const Term poly[]) {
int i = 0;

while (poly[i].coef != 0 || poly[i].exp != 0) {
if (i > 0 && poly[i].coef > 0) {
printf("+");
}

if (poly[i].coef != 1 && poly[i].coef != -1) {
printf("%.2f", poly[i].coef);
} else if (poly[i].coef == -1) {
printf("-");
}

if (poly[i].exp == 0) {
printf("%.2f", poly[i].coef);
} else if (poly[i].exp == 1) {
printf("x");
} else {
printf("x^%d", poly[i].exp);
}

i++;
}

printf("\n");
}