Generate a column vector y with the same number of elements as x that has evenly spaced values ranging from the minimum value in x to the maximum value in x.
时间: 2023-05-11 13:01:52 浏览: 73
您可以使用MATLAB中的linspace函数来生成一个列向量y,该向量具有与x相同的元素数量,其值从x中的最小值到最大值之间均匀分布。具体代码如下:
y = linspace(min(x), max(x), numel(x))'
相关问题
Set the crest factor and put 12.88 dB as a default value, which will display the peak-to-average ratio of the AWGN.in matlab
To set the crest factor and use 12.88 dB as the default value to calculate and display the peak-to-average ratio of AWGN in MATLAB, you can modify the previous code as follows:
```matlab
% Set parameters
N = 1000; % Length of the generated signal
SNR_dB = 12.88; % Default signal-to-noise ratio in dB
% Set crest factor in dB
crest_factor_dB = 12.88; % Crest factor in dB
% Generate original signal
x = randn(1, N); % Generate Gaussian random numbers with zero mean and unit variance
% Compute noise variance corresponding to the given SNR
SNR = 10^(SNR_dB / 10);
sigma = sqrt(var(x) / SNR);
% Generate noise
n = sigma * randn(1, N); % Generate Gaussian random numbers with zero mean and variance sigma^2
% Add noise to the original signal
y = x + n;
% Compute peak and average values
peak = max(abs(y)); % Compute peak value
average = mean(abs(y)); % Compute average value
% Calculate peak-to-average ratio (PAR) in dB
PAR_dB = 10 * log10(peak^2 / average^2);
% Display results
fprintf('Peak: %f\n', peak);
fprintf('Average: %f\n', average);
fprintf('Peak-to-Average Ratio (PAR): %.2f dB\n', PAR_dB);
```
In this code, after setting the crest factor in dB, we calculate the peak-to-average ratio (PAR) of the AWGN by taking the logarithm of the ratio of the squared peak value to the squared average value. The result is then displayed using `fprintf`.
. Write a program that generates a vector with 30 random integers between –20 and 20 and then finds the sum of all the elements that are divisible by 3.
Sure, here's the Python program to generate a vector with 30 random integers between -20 and 20 and find the sum of all the elements that are divisible by 3:
```python
import random
# Generate a list of 30 random integers between -20 and 20
vec = [random.randint(-20, 20) for _ in range(30)]
# Find the sum of all elements that are divisible by 3
div_by_3_sum = sum([num for num in vec if num % 3 == 0])
# Print the results
print("Generated vector:", vec)
print("Sum of all elements divisible by 3:", div_by_3_sum)
```
This program uses a list comprehension to generate a list of 30 random integers between -20 and 20. Then, it uses another list comprehension to find all the elements in the list that are divisible by 3 and calculates their sum using the `sum()` function. Finally, it prints the generated vector and the sum of all elements that are divisible by 3.