输入两个电阻值R1，R2和电压U，用C语言计算串联电流I1，并联电流I2

在电路理论中，串联和并联电流的计算基于欧姆定律。对于串联电路，总电压等于各个电阻上电压之和，而总电流则是相等的，因为它们通过相同的路径。对于并联电路，总电流则是各个支路电流之和。

串联电路的电流（I1）计算公式是：
\[ I_1 = \frac{U}{R_1 + R_2} \]

并联电路的电流（假设两个电阻是并联的，电流分别为I1和I2，总电流I总就是两者的和）：
\[ I_{总} = I_1 + I_2 \]
其中 \( I_2 = \frac{U}{R_2} \)

下面是一个简单的C语言函数示例，用于计算串联和并联电流：

#include <stdio.h>

// Function to calculate current in series
float calcSeriesCurrent(float R1, float R2, float U) {
    return U / (R1 + R2);
}

// Function to calculate total current in parallel
float calcParallelCurrent(float R1, float U) {
    float I1 = U / R1;
    return I1 + U / R1; // Assuming both resistors are identical for simplicity
}

int main() {
    float R1, R2, U;
    printf("Enter the resistance values (in ohms): R1 = ");
    scanf("%f", &R1);
    printf("R2 = ");
    scanf("%f", &R2);
    printf("Enter the voltage: U = ");
    scanf("%f", &U);

    float I_series = calcSeriesCurrent(R1, R2, U);
    float I_parallel = calcParallelCurrent(R1, U); // Assuming both resistances are same

    printf("Current in series (I1): %.2f A\n", I_series);
    printf("Total current in parallel (I_total): %.2f A\n", I_parallel);

    return 0;
}