假设电压为初始电压3.7V，容量为2000mAh，用电压法和电流积分综合估算电量写c语言的程序,程序需要带有三种状态,分别是电池充电,放电和边充边放.

#include <stdio.h>
#include <stdlib.h>

#define VOLTAGE 3.7
#define CAPACITY 2000
#define DELTA_T 1 // 时间间隔为1秒

enum BatteryState {
CHARGING,
DISCHARGING,
CHARGING_AND_DISCHARGING
};

float calculateVoltage(enum BatteryState state, float current, float voltage) {
float deltaQ, deltaV;

switch (state) {
case CHARGING:
deltaQ = current * DELTA_T;
deltaV = deltaQ / (CAPACITY / 1000);
voltage += deltaV;
break;
case DISCHARGING:
deltaQ = current * DELTA_T;
deltaV = deltaQ / (CAPACITY / 1000);
voltage -= deltaV;
break;
case CHARGING_AND_DISCHARGING:
deltaQ = (current > 0 ? current : 0) * DELTA_T;
deltaV = deltaQ / (CAPACITY / 1000);
voltage += deltaV;
deltaQ = (current < 0 ? -current : 0) * DELTA_T;
deltaV = deltaQ / (CAPACITY / 1000);
voltage -= deltaV;
break;
}

return voltage;
}

int main() {
float current, voltage = VOLTAGE, energy = CAPACITY / 1000 * VOLTAGE;
enum BatteryState state;

printf("Battery voltage: %fV\n", voltage);
printf("Battery energy: %fWh\n", energy / 1000);

while (1) {
printf("Enter current (- for discharge, + for charge, 0 for stop): ");
scanf("%f", &current);

if (current < 0) {
state = DISCHARGING;
} else if (current > 0) {
state = CHARGING;
} else {
state = CHARGING_AND_DISCHARGING;
}

voltage = calculateVoltage(state, current, voltage);
energy = CAPACITY / 1000 * voltage;

printf("Battery voltage: %fV\n", voltage);
printf("Battery energy: %fWh\n", energy / 1000);

if (voltage <= 3.0) {
printf("Battery low!\n");
}
}

return 0;
}