运用c语言编程实现银行家算法的基本过程，请将代码整合成一个完整的代码

以下是一个简单的银行家算法的C语言实现：

#include<stdio.h>

int main()
{
    int n, m, i, j, k;
    int available[10], max[10][10], allocation[10][10], need[10][10];
    int request[10], finish[10], seq[10], count = 0;

    printf("Enter the number of processes: ");
    scanf("%d", &n);

    printf("Enter the number of resources: ");
    scanf("%d", &m);

    printf("Enter the number of available resources: ");
    for(i = 0; i < m; i++)
        scanf("%d", &available[i]);

    printf("Enter the maximum demand of each process: ");
    for(i = 0; i < n; i++)
    {
        printf("\nProcess %d: ", i);
        for(j = 0; j < m; j++)
            scanf("%d", &max[i][j]);
    }

    printf("\nEnter the allocation for each process: ");
    for(i = 0; i < n; i++)
    {
        printf("\nProcess %d: ", i);
        for(j = 0; j < m; j++)
            scanf("%d", &allocation[i][j]);
    }

    for(i = 0; i < n; i++)
        for(j = 0; j < m; j++)
            need[i][j] = max[i][j] - allocation[i][j];

    printf("\nEnter the process requesting resources: ");
    scanf("%d", &k);

    printf("\nEnter the request: ");
    for(i = 0; i < m; i++)
        scanf("%d", &request[i]);

    for(i = 0; i < m; i++)
        if(request[i] > need[k][i])
        {
            printf("\nError: Requested resources exceed the maximum need!\n");
            return 0;
        }

    for(i = 0; i < m; i++)
        if(request[i] > available[i])
        {
            printf("\nError: Requested resources exceed the available resources!\n");
            return 0;
        }

    for(i = 0; i < m; i++)
    {
        available[i] -= request[i];
        allocation[k][i] += request[i];
        need[k][i] -= request[i];
    }

    for(i = 0; i < n; i++)
        finish[i] = 0;

    for(i = 0; i < n; i++)
    {
        for(j = 0; j < n; j++)
        {
            if(finish[j] == 0)
            {
                int flag = 1;
                for(k = 0; k < m; k++)
                    if(need[j][k] > available[k])
                    {
                        flag = 0;
                        break;
                    }

                if(flag)
                {
                    seq[count++] = j;
                    finish[j] = 1;
                    for(k = 0; k < m; k++)
                        available[k] += allocation[j][k];
                }
            }
        }
    }

    printf("\nSafe sequence: ");
    for(i = 0; i < n; i++)
        printf("%d ", seq[i]);

    printf("\n");

    return 0;
}

这个代码中，首先要求用户输入进程数、资源数、可用资源数、各进程最大需求、已分配资源等信息。然后要求用户输入一个特定进程的资源请求。接着，程序检查该请求是否超出了进程的最大需求和可用资源。如果请求合法，程序会更新系统状态并计算出一个安全序列。最后，程序输出安全序列。

请注意，这个实现仅作为基本示例，并不考虑很多实际情况。在实际应用中，需要根据具体情况进行调整和改进。