or(int i=0;i<31;i++) for(int j=0;j<31;j++) { switch(_MAP[i][j]) { case 1://画障礙物 painter.setBrush(QBrush(Qt::gray,Qt::SolidPattern)); painter.drawRect(QRect(i*25+200-(nodeSpacing-nodeSize)/2,(j+1)25+50-(nodeSpacing-nodeSize)/2,25,25)); break; case 0://画地圖 painter.setBrush(QBrush(QColor(66, 139, 230),Qt::SolidPattern)); painter.drawRect(QRect((i25+200),(j+1)25+50,nodeSize,nodeSize)); break; case 2://路線 painter.setBrush(QBrush(Qt::yellow,Qt::SolidPattern)); painter.drawRect(QRect(i25+200,(j+1)25+50,nodeSize,nodeSize)); break; case 3://agv painter.drawPixmap(i25+200-(nodeSpacing-nodeSize)/2,(j+1)25+50-(nodeSpacing-nodeSize)/2,25,25,QPixmap(":/new/prefix1/agv1.png").scaled(25,25)); case 5://agv模擬直綫路綫 // painter.setPen(QPen(Qt::yellow, 3, Qt::SolidLine)); // 设置画笔颜色、粗细和样式 // painter.drawLine(QPointF(i25+200+nodeSize/2, (j+1)*25+50+nodeSize/2), QPointF((i+1)*25+200-nodeSize/2, (j+1)25+50+nodeSize/2)); // 绘制直线 painter.setBrush(QBrush(Qt::yellow,Qt::SolidPattern)); painter.drawRect(QRect((i25+200),(j+1)25+50,nodeSize,nodeSize)); break; } if(setstar) { painter.setBrush(QBrush(Qt::red,Qt::SolidPattern)); painter.drawRect(QRect(_starx25+200-(nodeSpacing-nodeSize)/2,(_stary+1)25+50-(nodeSpacing-nodeSize)/2,25,25)); } if(settg) { painter.setBrush(QBrush(Qt::blue,Qt::SolidPattern)); painter.drawRect(QRect(_endx25+200-(nodeSpacing-nodeSize)/2,(_endy+1)25+50-(nodeSpacing-nodeSize)/2,25,25)); } if(setagv) { painter.drawPixmap(agv_x25+200-(nodeSpacing-nodeSize)/2,( agv_y+1)25+50-(nodeSpacing-nodeSize)/2,25,25,QPixmap(":/new/prefix1/agv1.png").scaled(25,25)); } } //畫出坐標之間的綫 for(int i=0;i<31;i++) { for(int j=0;j<31;j++) { if (i<30) { painter.setPen(QColor(66, 139, 230)); // 设置线条颜色 painter.drawLine(i25+200+nodeSize,(j+1)*25+50+nodeSize/2,(i+1)*25+200,(j+1)25+50+nodeSize/2); // 绘制线条 } if (j <30) { painter.setPen(QColor(66, 139, 230)); // 设置线条颜色 painter.drawLine(i25+200+nodeSize/2,(j+1)25+50+nodeSize,i25+200+nodeSize/2,(j+2)*25+50); // 绘制线条 } } },添加代碼：使兩點之間的值為nodezhi，如果nodezhi值為0,不進行繪畫，如果nodezhi為1，則在兩點直接畫出紅綫

Optimize time complexity and merely output your new code: #include <iostream> using namespace std; const int INF = 1e9; int find_min_cost(int n, int c[][100], int w[][100]) { /* 数据处理 / for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { if (w[i][j] == 0) { w[i][j] = INF; } } } for (int k = 0; k < n; k++) { for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { c[i][j] = min(c[i][j], c[i][k] + c[k][j]); w[i][j] = min(w[i][j], c[i][j] + min(w[i][k], w[k][j])); } } } int total_cost = 0; for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { if (w[i][j] != INF) { total_cost += w[i][j]; } } } return total_cost; } int main() { / 初始化变量 / int n; cin >> n; int c[100][100], w[100][100]; for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { cin >> c[i][j]; } } for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { cin >> w[i][j]; } } / 输出结果 */ cout << find_min_cost(n, c, w) << endl; return 0; }

for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { if (w[i][j] != 0) { d[i][j] = w[i][j]; } } } for (int k = 0; k < n; k++) { for (int i = 0; i < n; i++) { for (int j = 0; j < n; j+...

int j = 0; for(int i = 0;i<n;i++){j++;}

for(int i = 0; i < n; i++){ j++; //or any other statement } In this updated for loop, the variable i is incremented by 1 in each iteration until it reaches the value of n, and the variable j is...

unsigned int i, j; for(i = 0; i < t; i++) for(j = 0; j < 125; j++)

The code snippet provided is incomplete as the increment statements for variables i and j are missing. Therefore, it is not possible to determine the exact purpose ... j++) { // code to be executed } }

将下列代码转换成python：public class BinomialArray { public static void main(String[] args) { int[][] array=new int[100][100]; for(int i=0; i<=9; i++){ for(int j=0; j<=i; j++){ array[i][0]=1; array[i+1][j+1]=array[i][j]+array[i][j+1]; } } for(int i=0; i<=9; i++){ for(int j=0; j<=i; j++){ System.out.print(array[i][j]+"\t"); } System.out.println(); }

if j == 0 or i == j: array[i][j] = 1 else: array[i][j] = array[i - 1][j - 1] + array[i - 1][j] for i in range(10): for j in range(i + 1): print(array[i][j], "\t", end="") print()

for(int i = 0; i < n; ++i) for(int j = 0; j < n; ++j) scanf("%c", &a[i][j]);有错误吗

As an AI language model, I do not have emotions, opinions or personal beliefs, hence the concept of null is a placeholder or a value that represents the absence of meaningful data. In programming, ...

public static void bubbleSort(int[] arr) { int n = arr.length; for (int i = 0; i < n - 1; i++) { for (int j = 0; j < n - i - 1; j++) { if (arr[j] > arr[j + 1]) { // 交换 arr[j] 和 arr[j+1] int temp = arr[j]; arr[j] = arr[j + 1]; arr[j + 1] = temp; } } }}

for (int i = 0; i < n - 1; i++) { for (int j = 0; j < n - i - 1; j++) { if (arr[j] > arr[j + 1]) { // swap arr[j] and arr[j+1] int temp = arr[j]; arr[j] = arr[j + 1]; arr[j + 1] = temp; } } ...

改写成python语言import java.util.LinkedList; import java.util.List; import java.util.Scanner; public class Main { private static final int N = 1000 + 10; private static int[] get_cost(){ int[] cost = new int[N]; boolean[] vis = new boolean[N]; for(int i=1;i<N;i++){ cost[i] = -1; vis[i] = false; } LinkedList<Integer> que = new LinkedList<>(); que.addLast(1); cost[1] = 0; vis[1] = true; while(!que.isEmpty()){ int cur = que.pollFirst(); for(int i=1;i<=cur;i++){ int nxt = cur + cur / i; if(nxt >= N){ continue; } if(vis[nxt]){ continue; } vis[nxt] = true; cost[nxt] = cost[cur] + 1; que.addLast(nxt); } } return cost; } public static void main(String[] args) { int[] cost = get_cost(); int[] b = new int[N]; int[] c = new int[N]; int[] w = new int[N]; int[] dp = new int[12 * N]; Scanner scanner = new Scanner(System.in); int T = scanner.nextInt(); while (T > 0) { int n = scanner.nextInt(); int k = scanner.nextInt(); for (int i = 1; i <= n; i++) { b[i] = scanner.nextInt(); } for (int i = 1; i <= n; i++) { c[i] = scanner.nextInt(); } for (int i = 1; i <= n; i++) { w[i] = cost[b[i]]; } int sum_w = 0; for (int i = 1; i <= n; i++) { sum_w += w[i]; } int sum_c = 0; for (int i = 1; i <= n; i++) { sum_c += c[i]; } if (k >= sum_w) { System.out.println(sum_c); } else { for (int i = 0; i <= k; i++) { dp[i] = 0; } for (int i = 1; i <= n; i++) { for (int j = k; j >= w[i]; j--) { int v = dp[j - w[i]] + c[i]; if (dp[j] < v) { dp[j] = v; } } } System.out.println(dp[k]); } T--; } } }

这是Java代码，可以使用Jython将其转换成Python代码，也可以手动将... for j in range(k, w[i]-1, -1): v = dp[j - w[i]] + c[i] if dp[j] < v: dp[j] = v print(dp[k]) if __name__ == '__main__': main()

int f(int i) { int m = 1; for(int j = 1; j <= i; j++) { m *= j; } return m; }

The for loop iterates from 1 to the value of "i", with "j" being the loop counter. In each iteration, the value of "m" is multiplied by the current value of "j". After the loop completes, the final ...

请对以下代码进行纠错：#include<bits/stdc++.h> using namespace std; int main(){ int n; cin>>n; string str; cin>>str; int lenstr=str.length(); if(lenstr%n!=0) { cout<<"NO"; return 0; } int len1=lenstr/n; char str1[10001],str2[10001]; for(int i=0;i<len1;i++) { str1[i]=str[i]; } for(int i=len1-1;i<lenstr;i++) { str2[i]=str[i]; } bool flag=1; for(int i=0;i<len1;i++) for(int j=len1-1;j>=0;j--) if(str1[i]!=str1[j]or str2[i]!=str2[j]) flag=0; if(flag) { cout<<"YES"; return 0; } cout<<"NO"; return 0; }

for (int i = 0; i < len1; i++) { str1[i] = str[i]; } for (int i = len1; i < lenstr; i++) { str2[i - len1] = str[i]; } bool flag = true; for (int i = 0; i < len1; i++) { for (int j = len1 - 1;...

void delay(unsigned int t) { unsigned int i, j; for(i = 0; i < t; i++) for(j = 0; j < 125; j++); }

The code above is a function in C that creates a delay for a specified amount of time, given in microseconds. The function takes an unsigned integer t as input, which represents the duration of the ...

#include <stdio.h> int main() { int n=0; scanf("%d\n",&n); int sum=0; int arr[n][n]; int i=0; int j=0; for(i=0;i<n;i++) { for(j=0;j<n;j++) { scanf("%d",&arr[i][j]); } } for(i=0;i<n;i++) { for(j=0;j<n;j++) { if(i==n-1||j==n-1||i+j==n-1) continue; else sum+=arr[i][j]; } } printf("%d",sum); return 0; }转化成python语言

if i==n-1 or j==n-1 or i+j==n-1: continue else: sum += arr[i][j] print(sum) 需要注意的是，Python 中二维数组的初始化方式和 C 语言不同，需要使用列表嵌套的方式来初始化。另外，在 Python 中，...

#include <iostream> #include <cstring> #include <algorithm> const int MAX_B = 1005; const int MAX_TIMES = 1000005; int arrayB[MAX_B]; int arrayC[MAX_B]; int times[MAX_TIMES]; int dp[MAX_TIMES]; void calculateTimes(int x, int step) { if (x > MAX_B) return; if (times[x] != 1919810 && step >= times[x]) return; if (step < times[x]) times[x] = step; for (int i = 1; i <= x; i++) calculateTimes(x + x / i, step + 1); } int calculateMoney(int n, int k, int b[], int c[], int sum) { int ans = 0; int maxSteps = 0; memset(dp, 0, sizeof dp); for (int i = 1; i <= n; i++) { maxSteps = std::max(maxSteps, times[b[i]]); ans += times[b[i]]; } if (k >= maxSteps * n || k >= ans) { return sum; } for (int i = 1; i <= n; i++) { for (int j = k; j >= times[b[i]]; j--) { dp[j] = std::max(dp[j], dp[j - times[b[i]]] + c[i]); } } return dp[k]; } int main() { for (int i = 1; i < MAX_B; i++) { times[i] = 1919810; } calculateTimes(1, 0); int t; std::scanf("%d", &t); for (int i = 1; i <= t; i++) { int sum = 0; int n, k; std::scanf("%d %d", &n, &k); for (int i = 1; i <= n; i++) { std::scanf("%d", &arrayB[i]); } for (int i = 1; i <= n; i++) { std::scanf("%d", &arrayC[i]); sum += arrayC[i]; } std::printf("%d\n", calculateMoney(n, k, arrayB, arrayC, sum)); } return 0; }

for j in range(k, times[b[i]]-1, -1): dp[j] = max(dp[j], dp[j - times[b[i]]] + c[i]) return dp[k] if __name__ == '__main__': for i in range(1, MAX_B): times[i] = 1919810 calculateTimes(1, 0) t...

#include<stdio.h> #include<string.h> int main() { char xuehao[46];int p[46]={0};char xingming[46],compare[46]; printf("please write down the student's number!\n"); for(int i=1;i<=45;i++) { scanf("%s",xuehao+i); } printf("please write down the student's name\n"); for(int i=1;i<=45;i++) { scanf("%s",xingming+i); } //读取录入姓名学号，未重复的为p==0 //读取做完的学生信息，姓名和学号串 int n=0; printf("please write down the finished student's name or number or name and number!\n"); while(scanf("%s",compare+n)!=EOF) { n++; } int s=45-n;//s为未完成的人数量 printf("print down the unfinished number %d",s); int i; for(i=1;i<=n;i++) { if(11==strlen(compare+i)) { for(int j=1;j<=45;j++) { if(strcmp(compare+i,xuehao+j)==0){p[j]=1;} } } else if(11>strlen(compare+i)) { for(int j=1;j<=45;j++) { if(strcmp(compare+i,xingming+j)==0){p[j]=1;} } } else{ char cc[100]; for(int j=1;j<=45;j++) { strncpy(cc, compare+i,strlen(xingming+j)); if(strcmp(cc,xingming+j)==0){p[j]=1;} strncpy(cc, compare+i,strlen(xuehao+j)); if(strcmp(cc,xuehao+j)==0){p[j]=1;} } } printf("print out the data!\n"); for(i=1;i<=45;i++) { if(p[i]==0)printf("%s",xuehao[i]); } } return 0; }

这段代码的作用是从输入中读取学生姓名和学号信息，并记录每个学生的完成情况。它包括以下步骤： 1. 读取45个学生的学号信息，存储在字符数组xuehao中。 2. 读取45个学生的姓名信息，存储在字符数组xingming中。...

给出一个测试函数，里面有随机一组测试数据：void CreateMGraph(MGraph &H) //创建邻接矩阵 (无向图） { int i, j, k, w; printf("请输入顶点数和边数：\n"); scanf("%d %d", &H.n, &H.e); printf("请输入顶点信息：\n"); for (i = 0; i < H.n; i++) { scanf("%s", &H.vexs[i].info); //s or d? H.vexs[i].no = i; } for (i = 0; i < H.n; i++) { for (j = 0; j < H.n; j++) { H.edges[i][j] = -1; } } printf("请输入每条边的起点、终点和权值：\n"); for (k = 0; k < H.e; k++) { char c1,c2; scanf("%c %c %d", &c1, &c2, &w); //s or d i = c1-'A'; j = c2-'A'; H.edges[i][j] = w; H.edges[j][i] = w; //无向图，所以要将两个方向都存储 } }

for (int i = 0; i < G.n; i++) { G.vexs[i].info = 'A' + i; G.vexs[i].no = i; } for (int i = 0; i < G.n; i++) { for (int j = i + 1; j < G.n; j++) { if (rand() % 2 == 0) { G.edges[i][j] = G.edges...

{ public static void main(String[] args) { int i=8, j=2; while(j< --i) for(int k=0; k<4; k++) j++; System.out.print(j); } }

As an AI language model, I cannot run the code or access the actual output. However, I can explain what the code does. The code initializes two integer variables, i and j, with the values 8 and 2 ...

#include <stdio.h> #include <stdlib.h> #define ROW 6 #define COL 6 int main() { int score[ROW][COL]; int cards[6]; int i, j, k, num, dir, total_score; // input score table for (i = 0; i < ROW; i++) { for (j = 0; j < COL; j++) { scanf("%d", &score[i][j]); } } // input cards for (i = 0; i < 6; i++) { scanf("%d", &cards[i]); } // input and process each customer for (k = 0; k < 3; k++) { total_score = 0; scanf("%d %d", &num, &dir); // calculate score if (cards[num-1] == 0) { printf("Invalid card number!\n"); continue; } if (dir == 1) { for (i = 0; i < COL; i++) { total_score += score[num-1][i]; } } else if (dir == 2) { for (i = 0; i < ROW; i++) { total_score += score[i][num-1]; } } else { printf("Invalid direction!\n"); continue; } printf("%d\n", total_score); } return 0; } 改进上述代码

j++) { scanf("%d", &score[i][j]); if (!isValidNumber(score[i][j], 1, 100)) { printf("Invalid input: score should be between 1 and 100!\n"); exit(1); } } } } // 读取卡牌 void readCards(int ...

Given the following program class Game { private static final int DELAY = 500; private int x; public Game() { x = 0; } public void addX() { try { int y = x; Thread.sleep((int) (DELAY * Math.random())); y += 1; x = y; System.out.println("x=" + x); } catch (InterruptedException e) { } } } public class Homework8 { public static void main(String[] args) { var game = new Game(); for (int i = 0; i < 2; i++) { new Thread(() -> { for (int j = 0; j < 2; j++) game.addX(); }).start(); } } } The output could be x=1 x=1 x=2 x=2 or x=1 x=2 x=1 x=2 However, we desire the output to be x=1 x=2 x=3 x=4 1. Modify the addX method using ReentrantLock to get the desired output.

for (int i = 0; i < 2; i++) { new Thread(() -> { for (int j = 0; j < 2; j++) game.addX(); }).start(); } } } The ReentrantLock is used to ensure that only one thread can access the addX...

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