使用C语言，写一个程序 n1为54，n2

为13，计算它们的和、差、积、商、余数和平均数。

代码如下：

#include <stdio.h>

int main() {
    int n1 = 54, n2 = 13;
    int sum = n1 + n2;
    int difference = n1 - n2;
    int product = n1 * n2;
    int quotient = n1 / n2;
    int remainder = n1 % n2;
    float average = (float)(n1 + n2) / 2;

    printf("n1 = %d, n2 = %d\n", n1, n2);
    printf("sum = %d\n", sum);
    printf("difference = %d\n", difference);
    printf("product = %d\n", product);
    printf("quotient = %d\n", quotient);
    printf("remainder = %d\n", remainder);
    printf("average = %.2f\n", average);

    return 0;
}

输出结果如下：

n1 = 54, n2 = 13
sum = 67
difference = 41
product = 702
quotient = 4
remainder = 2
average = 33.50

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c语言：计算正整数n1到n2的累加和（n1,n2的值由键盘输入）

以下是计算正整数n1到n2的累加和的C语言代码示例：

#include <stdio.h>

int main() {
    int n1, n2, sum = 0;
    
    printf("请输入两个正整数n1和n2：");
    scanf("%d %d", &n1, &n2);
    
    for (int i = n1; i <= n2; i++) {
        sum += i;
    }
    
    printf("sum = %d", sum);
    
    return 0;
}