left.ts = right.ts is expected in join expression

这个错误通常发生在数据库查询中进行多表连接时，因为在连接条件中使用了不正确的语法。在多表连接中，连接条件应该是一个布尔表达式，用来指定连接两个表的行的规则。在这个错误中，出现了"left.ts = right.ts"的表达式，这通常是因为连接条件中使用了不正确的字段名或者表别名。请检查连接条件并确保使用正确的字段名和表别名。

相关问题

struct node enode, node, q[100] main9(int n,float m) {int f=0,e=0; float bestp = 0,beste = 0; enode.cw=0; enode.cp= 0; enode.i=0; enode,flag= 0 enode.par = 0; e=e+1; g[e] = enode; while(e<>0) {node.cw = enode.cw + w[enode.i + 1]; if(node,cw<=m) {node.cp = enode.cp + p[enode.i+1]; if(node.cp> bestp) {bestp = node.cp; beste=e+1;} node.flag= 1; node.par = f; node.i= enode.i+1; e=e+1; q[e]= node;} node.cw = enode.cw; node.cp = enode.cp; node.flag=0; node.par=f; node.i= enode.i+1; e=e+1; q[e]= node; f=f+1 enode = q[f];} for (intj=l;j>=n;j=j+1) {if(q[baste].flag=1) print("choose",q[baste].i); baste = q[ baste].par;} print("Max=",bestp);}转换成python语言的代码

Unfortunately, the given code snippet is incomplete and contains syntax errors. However, I will provide a rough translation of the code to Python, assuming that the missing parts are defined elsewhere in the code:

class Node:
    def __init__(self, cw=0, cp=0, i=0, flag=0, par=0):
        self.cw = cw
        self.cp = cp
        self.i = i
        self.flag = flag
        self.par = par

n = ...
m = ...

enode = Node()
enode.cw = 0
enode.cp = 0
enode.i = 0
enode.flag = 0
enode.par = 0

q = [Node() for _ in range(100)]
g = [Node() for _ in range(n)]
f = 0
e = 0
bestp = 0
beste = 0

e += 1
g[e] = enode

while e != 0:
    node = Node()
    node.cw = enode.cw + w[enode.i + 1]
    if node.cw <= m:
        node.cp = enode.cp + p[enode.i + 1]
        if node.cp > bestp:
            bestp = node.cp
            beste = e + 1
        node.flag = 1
        node.par = f
        node.i = enode.i + 1
        e += 1
        q[e] = node
    node.cw = enode.cw
    node.cp = enode.cp
    node.flag = 0
    node.par = f
    node.i = enode.i + 1
    e += 1
    q[e] = node
    f += 1
    enode = q[f]

for j in range(n, l+1):
    if q[beste].flag == 1:
        print("choose", q[beste].i)
    beste = q[beste].par

print("Max=", bestp)

Note that this translation may not work as expected, since the original code is incomplete and contains syntax errors. Furthermore, I had to make some assumptions about the missing parts of the code, so the translation may not be accurate.

expected expression before '=' token yylval.nvalue = atoi(yytext);

这个错误是由于在某个位置出现了语法错误，导致编译器无法识别等号左边的标识符。在这个特定的错误消息中，可能是因为 "yylval.nvalue" 的上下文被中断了，导致编译器无法识别它。可能的原因是在该行代码之前的某个地方存在语法错误，或者该行代码中的其他部分存在错误。请检查代码，查找其他可能的错误，修复它们，然后再试一次。