帮我写一个C语言函数，把字符串C4:CB:54:08:EA:57，去除冒号，转换成6个16进制数字

以下是一个简单的实现：

#include <stdio.h>
#include <string.h>

void convertMacAddress(char* macAddress, unsigned char* hexDigits) {
    int i, j;
    char buf[3] = {0};
    for (i = 0, j = 0; i < strlen(macAddress); i++) {
        if (macAddress[i] != ':') {
            buf[j++] = macAddress[i];
        }
        if (j == 2) {
            sscanf(buf, "%x", &hexDigits[i/2]);
            j = 0;
        }
    }
}

int main() {
    char macAddress[] = "C4:CB:54:08:EA:57";
    unsigned char hexDigits[6] = {0};
    convertMacAddress(macAddress, hexDigits);
    printf("%02X %02X %02X %02X %02X %02X\n", hexDigits[0], hexDigits[1], hexDigits[2], hexDigits[3], hexDigits[4], hexDigits[5]);
    return 0;
}

输出结果为：

C4 CB 54 08 EA 57