51单片机用8位数码管显示出学号
时间: 2024-05-06 22:17:29 浏览: 562
假设学号为"20210001",可以通过以下步骤实现:
1. 定义8个引脚分别连接到8位数码管的8个引脚,以及一个引脚连接到数码管的位选引脚。
2. 在51单片机上编写程序,将学号的每一位数字转换为对应的数码管段码,存储到一个数组中。
3. 循环遍历该数组,每次将一个数码管段码输出到相应的数码管引脚上,并同时将当前数码管的位选引脚输出高电平,使该数码管被选中亮起。
4. 程序每次循环后,将位选引脚向下移动一位,以便选择下一个数码管。
以下是一个简单的示例代码:
```
#include <reg51.h> // 51单片机头文件
// 数码管段码定义
unsigned char code segCode[] = {
0x3F, // 0
0x06, // 1
0x5B, // 2
0x4F, // 3
0x66, // 4
0x6D, // 5
0x7D, // 6
0x07, // 7
0x7F, // 8
0x6F // 9
};
// 数码管引脚定义
sbit D1 = P0^0;
sbit D2 = P0^1;
sbit D3 = P0^2;
sbit D4 = P0^3;
sbit D5 = P0^4;
sbit D6 = P0^5;
sbit D7 = P0^6;
sbit D8 = P0^7;
sbit WE = P1^0;
void main() {
unsigned char code stuNo[] = "20210001"; // 学号
unsigned char i = 0; // 循环计数器
while (1) {
// 输出当前数码管的段码
switch (i) {
case 0:
D1 = segCode[stuNo[i] - '0'];
break;
case 1:
D2 = segCode[stuNo[i] - '0'];
break;
case 2:
D3 = segCode[stuNo[i] - '0'];
break;
case 3:
D4 = segCode[stuNo[i] - '0'];
break;
case 4:
D5 = segCode[stuNo[i] - '0'];
break;
case 5:
D6 = segCode[stuNo[i] - '0'];
break;
case 6:
D7 = segCode[stuNo[i] - '0'];
break;
case 7:
D8 = segCode[stuNo[i] - '0'];
break;
}
// 输出位选引脚高电平,选择当前数码管
switch (i) {
case 0:
WE = 0xFE;
break;
case 1:
WE = 0xFD;
break;
case 2:
WE = 0xFB;
break;
case 3:
WE = 0xF7;
break;
case 4:
WE = 0xEF;
break;
case 5:
WE = 0xDF;
break;
case 6:
WE = 0xBF;
break;
case 7:
WE = 0x7F;
break;
}
// 延时一段时间,保证数码管刷新
for (int j = 0; j < 100; j++);
// 将位选引脚向下移动一位
WE = 0xFF;
// 指向下一个数码管
i++;
if (i >= 8) i = 0;
}
}
```
注意,此代码仅为示例,实际应用中还需要根据具体硬件调整引脚定义和位选引脚输出顺序等。
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