hailstone sequence java
时间: 2023-04-22 12:04:40 浏览: 171
哈尔斯通序列(Hailstone sequence)是一个数学问题,也称为“冰雹序列”或“角谷猜想”。它是由一个正整数开始,然后根据以下规则生成序列:
如果当前数字为偶数,则将其除以2;
如果当前数字为奇数,则将其乘以3并加1;
重复上述步骤,直到序列最终收敛于1。
Java程序可以用递归或循环来实现哈尔斯通序列的计算。例如,以下是一个使用递归的Java程序:
public static void hailstone(int n) {
System.out.print(n + " ");
if (n == 1) return;
if (n % 2 == ) hailstone(n / 2);
else hailstone(n * 3 + 1);
}
在这个程序中,我们首先打印当前数字n,然后根据它是偶数还是奇数,递归地调用hailstone函数,直到n等于1为止。
相关问题
Write a generator that outputs the hailstone sequence from hw01. Here's a quick reminder of how the hailstone sequence is defined: Pick a positive integer n as the start. If n is even, divide it by 2. If n is odd, multiply it by 3 and add 1. Continue this process until n is 1. For some extra practice, try writing a solution using recursion. Since hailstone returns a generator, you can yield from a call to hailstone!
Sure! Here's an implementation of the `hailstone` generator function:
```python
def hailstone(n):
yield n
while n != 1:
n = n // 2 if n % 2 == 0 else 3 * n + 1
yield n
```
This generator function takes a positive integer `n` as the start of the hailstone sequence, and generates each subsequent number in the sequence until it reaches 1.
The function first yields the starting number `n`, and then enters a loop that continues until `n` is equal to 1. In each iteration of the loop, the function computes the next number in the sequence based on whether `n` is even or odd, and yields that number. If `n` is even, the function divides it by 2 using integer division (`//`). If `n` is odd, the function multiplies it by 3 and adds 1.
Here's an example usage of this generator function:
```python
>>> list(hailstone(10))
[10, 5, 16, 8, 4, 2, 1]
```
This example generates the hailstone sequence starting from 10, which is `[10, 5, 16, 8, 4, 2, 1]`. The `list` function is used to consume all the elements of the generator and return them as a list.
冰雹猜想python数组代码
冰雹猜想(Hailstone conjecture),也被称为冰雹序列(Hailstone sequence)或者3n+1问题,是一个数学问题。该问题的规则如下:
给定一个正整数n,如果n是偶数,则将其除以2;如果n是奇数,则将其乘以3再加1。重复这个过程,直到n等于1为止。冰雹猜想认为,对于任意一个正整数n,最终都会得到1。
以下是使用Python编写的冰雹猜想的数组代码示例:
```python
def hailstone(n):
sequence = [n] # 用于存储冰雹序列的数组
while n != 1:
if n % 2 == 0:
n = n // 2
else:
n = n * 3 + 1
sequence.append(n)
return sequence
# 测试代码
n = int(input("请输入一个正整数:"))
sequence = hailstone(n)
print("冰雹序列为:", sequence)
```
这段代码定义了一个名为`hailstone`的函数,接受一个正整数n作为参数,并返回冰雹序列。在函数内部,使用一个while循环来不断进行除以2或者乘以3加1的操作,直到n等于1为止。每次操作后,将得到的结果添加到序列中。最后,打印出冰雹序列。