使用结构数组存放下表中的员工的工资数据，然后用结构指针输出每个员工的姓名及应发工资数。 应发工资=基本工资+岗位津贴-扣款 姓名 基本工资 岗位津贴 扣款 liqun dongfang majing liudong 870.00 1250.00 1520.00 2050.00 500.00 800.00 1000.00 1500.00 85．00 63．00 72．00 120.00

好的，这是一个比较简单的结构体数组操作，可以按照以下步骤进行：

1. 定义结构体，包含姓名、基本工资、岗位津贴、扣款和应发工资字段。

struct Employee {
    char name[20];
    float basic_salary;
    float position_allowance;
    float deduction;
    float gross_salary;
};

2. 定义结构体数组，初始化每个员工的数据。

struct Employee employees[] = {
    {"liqun", 870.00, 500.00, 85.00},
    {"dongfang", 1250.00, 800.00, 63.00},
    {"majing", 1520.00, 1000.00, 72.00},
    {"liudong", 2050.00, 1500.00, 120.00}
};

3. 计算每个员工的应发工资，并保存到结构体数组中。

for (int i = 0; i < 4; i++) {
    float gross_salary = employees[i].basic_salary + employees[i].position_allowance - employees[i].deduction;
    employees[i].gross_salary = gross_salary;
}

4. 定义结构指针，遍历结构体数组，输出每个员工的姓名和应发工资。

struct Employee *p;
for (p = employees; p < employees + 4; p++) {
    printf("%s\t%.2f\n", p->name, p->gross_salary);
}

完整代码如下：

#include <stdio.h>

struct Employee {
    char name[20];
    float basic_salary;
    float position_allowance;
    float deduction;
    float gross_salary;
};

int main() {
    struct Employee employees[] = {
        {"liqun", 870.00, 500.00, 85.00},
        {"dongfang", 1250.00, 800.00, 63.00},
        {"majing", 1520.00, 1000.00, 72.00},
        {"liudong", 2050.00, 1500.00, 120.00}
    };

    for (int i = 0; i < 4; i++) {
        float gross_salary = employees[i].basic_salary + employees[i].position_allowance - employees[i].deduction;
        employees[i].gross_salary = gross_salary;
    }

    struct Employee *p;
    for (p = employees; p < employees + 4; p++) {
        printf("%s\t%.2f\n", p->name, p->gross_salary);
    }

    return 0;
}