// 集合交运算 Set intersection(Set set1, Set set2) { Set set; init(&set); Node* p = set1.head; while (p != NULL) { if (strstr(set2.head, &(p->data)) != NULL) { insert(&set, p->data); } p = p->next; } return set; } // 集合并运算 Set union_set(Set set1, Set set2) { Set set; init(&set); Node* p = set1.head; while (p != NULL) { insert(&set, p->data); p = p->next; } p = set2.head; while (p != NULL) { if (strstr(set.head, &(p->data)) == NULL) { insert(&set, p->data); } p = p->next; } return set; } // 集合差运算 Set difference(Set set1, Set set2) { Set set; init(&set); Node* p = set1.head; while (p != NULL) { if (strstr(set2.head, &(p->data)) == NULL) { insert(&set, p->data); } p = p->next; } return set; }
时间: 2024-03-11 12:44:26 浏览: 59
这段代码实现了集合的交、并、差等运算。其中交运算(intersection)遍历集合1中的所有元素,如果该元素也在集合2中则将其加入到新集合中。并运算(union_set)先将集合1中的所有元素加入到新集合中,再遍历集合2中的所有元素,如果该元素不在新集合中则将其加入到新集合中。差运算(difference)遍历集合1中的所有元素,如果该元素不在集合2中则将其加入到新集合中。这些运算都使用了集合的初始化、插入元素等基本操作来构造新的集合。需要注意的是在判断字符在集合中是否存在时使用了 strstr 函数,该函数常用于判断字符串中是否包含指定字符串。在这里可以用来判断字符是否在集合中。
相关问题
]编制一个能演示执行集合的并、交和差运算的程序。[基本要求]集合的元素限定为小写字母字符 [‘a’..’z’],使用链表完成。[测试数据](1)输入:set1=\"magazine\",set2=\"pap
### 回答1:
er\",输出:并集为:aegimnpz,交集为:ae,差集为:gimnz。
(2)输入:set1=\"hello\",set2=\"world\",输出:并集为:dehlorw,交集为:lo,差集为:eh。
### 回答2:
下面是一个能够演示执行集合并、交和差运算的程序,其集合的元素限定为小写字母字符[a..z],使用链表完成。
```python
# 创建链表节点类
class Node:
def __init__(self, data):
self.data = data
self.next = None
# 创建集合类
class Set:
def __init__(self):
self.head = None
# 向集合中添加元素
def add(self, data):
node = Node(data)
if self.head is None:
self.head = node
else:
current = self.head
while current.next:
current = current.next
current.next = node
# 遍历并输出集合的元素
def display(self):
current = self.head
while current:
print(current.data, end = " ")
current = current.next
print("")
# 集合并运算
def union(self, other_set):
new_set = Set()
current = self.head
while current:
new_set.add(current.data)
current = current.next
current = other_set.head
while current:
if not self.contains(current.data):
new_set.add(current.data)
current = current.next
return new_set
# 集合交运算
def intersection(self, other_set):
new_set = Set()
current = self.head
while current:
if other_set.contains(current.data):
new_set.add(current.data)
current = current.next
return new_set
# 集合差运算
def difference(self, other_set):
new_set = Set()
current = self.head
while current:
if not other_set.contains(current.data):
new_set.add(current.data)
current = current.next
return new_set
# 判断集合中是否包含某个元素
def contains(self, element):
current = self.head
while current:
if current.data == element:
return True
current = current.next
return False
# 测试数据
set1 = Set()
set1.add('m')
set1.add('a')
set1.add('g')
set1.add('a')
set1.add('z')
set1.add('i')
set1.add('n')
set1.add('e')
set2 = Set()
set2.add('p')
set2.add('a')
set2.add('p')
# 执行集合并运算
union_set = set1.union(set2)
print("集合并运算结果:")
union_set.display()
# 执行集合交运算
intersection_set = set1.intersection(set2)
print("集合交运算结果:")
intersection_set.display()
# 执行集合差运算
difference_set = set1.difference(set2)
print("集合差运算结果:")
difference_set.display()
```
希望对你有帮助!
### 回答3:
下面是一个能够演示执行并、交和差运算的程序:
```python
class Node:
def __init__(self, value):
self.value = value
self.next = None
class Set:
def __init__(self):
self.head = None
def insert(self, value):
if self.head is None:
self.head = Node(value)
else:
current = self.head
while current.next:
current = current.next
current.next = Node(value)
def display(self):
elements = []
current = self.head
while current:
elements.append(current.value)
current = current.next
print(elements)
def union(set1, set2):
union_set = Set()
current = set1.head
while current:
union_set.insert(current.value)
current = current.next
current = set2.head
while current:
if not is_present(union_set, current.value):
union_set.insert(current.value)
current = current.next
return union_set
def intersection(set1, set2):
intersection_set = Set()
current = set1.head
while current:
if is_present(set2, current.value):
intersection_set.insert(current.value)
current = current.next
return intersection_set
def difference(set1, set2):
difference_set = Set()
current = set1.head
while current:
if not is_present(set2, current.value):
difference_set.insert(current.value)
current = current.next
return difference_set
def is_present(set, value):
current = set.head
while current:
if current.value == value:
return True
current = current.next
return False
set1 = Set()
set2 = Set()
set1_string = "magazine"
set2_string = "pap"
for char in set1_string:
set1.insert(char)
for char in set2_string:
set2.insert(char)
print("Set1:")
set1.display()
print("Set2:")
set2.display()
print("Union:")
union_set = union(set1, set2)
union_set.display()
print("Intersection:")
intersection_set = intersection(set1, set2)
intersection_set.display()
print("Difference:")
difference_set = difference(set1, set2)
difference_set.display()
```
该程序首先定义了一个`Node`类来表示链表中的节点,然后定义了`Set`类来表示集合。`Set`类具有插入元素和展示集合元素的功能。接下来定义了并、交和差三种集合运算的函数,并使用`Set`类的实例来执行这些运算。最后,创建了两个集合并将测试数据插入到集合中,然后展示了集合的元素,执行了并、交和差运算,并展示了结果。
用有序单链表表示集合,实现集合的交、并、差运算
以下是用Python语言实现集合交、并、差运算的示例代码,其中假设链表中的元素为整数:
```python
class Node:
def __init__(self, val=None, next=None):
self.val = val
self.next = next
class Set:
def __init__(self):
self.head = None
# 在集合中添加元素
def add(self, val):
if not self.contains(val):
new_node = Node(val)
new_node.next = self.head
self.head = new_node
# 判断集合中是否包含某个元素
def contains(self, val):
curr = self.head
while curr:
if curr.val == val:
return True
curr = curr.next
return False
# 集合的交运算
def intersection(self, other):
result = Set()
curr = self.head
while curr:
if other.contains(curr.val):
result.add(curr.val)
curr = curr.next
return result
# 集合的并运算
def union(self, other):
result = Set()
curr = self.head
while curr:
result.add(curr.val)
curr = curr.next
curr = other.head
while curr:
result.add(curr.val)
curr = curr.next
return result
# 集合的差运算
def difference(self, other):
result = Set()
curr = self.head
while curr:
if not other.contains(curr.val):
result.add(curr.val)
curr = curr.next
return result
```
使用示例:
```python
# 创建两个集合
set1 = Set()
set2 = Set()
# 添加元素
set1.add(1)
set1.add(2)
set1.add(3)
set2.add(3)
set2.add(4)
set2.add(5)
# 集合的交运算
result = set1.intersection(set2)
curr = result.head
while curr:
print(curr.val)
curr = curr.next
# 输出:3
# 集合的并运算
result = set1.union(set2)
curr = result.head
while curr:
print(curr.val)
curr = curr.next
# 输出:1 2 3 4 5
# 集合的差运算
result = set1.difference(set2)
curr = result.head
while curr:
print(curr.val)
curr = curr.next
# 输出:1 2
```
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