俄罗斯方块的源代码
时间: 2023-08-31 14:05:43 浏览: 101
由于俄罗斯方块是一个经典的游戏,其源代码已经在许多不同的编程语言中被实现。以下是一个基于Python语言的简单俄罗斯方块游戏的示例代码:
```python
import pygame
import random
# 定义方块形状
shapes = [
[[1, 1, 1], [0, 1, 0]],
[[0, 2, 2], [2, 2, 0]],
[[3, 3, 0], [0, 3, 3]],
[[4, 0, 0], [4, 4, 4]],
[[0, 0, 5], [5, 5, 5]],
[[6, 6], [6, 6]]
]
# 设置方块颜色
colors = [
(0, 0, 0),
(255, 0, 0),
(0, 255, 0),
(0, 0, 255),
(255, 255, 0),
(0, 255, 255),
(255, 0, 255)
]
class Block:
def __init__(self, x, y, shape):
self.x = x
self.y = y
self.shape = shape
self.color = random.randint(1, len(colors) - 1)
def rotate(self):
self.shape = [[self.shape[y][x] for y in range(len(self.shape))] for x in range(len(self.shape[0]) - 1, -1, -1)]
def move(self, dx):
self.x += dx
def draw(self, surface):
for i in range(len(self.shape)):
for j in range(len(self.shape[i])):
if self.shape[i][j] > 0:
pygame.draw.rect(surface, colors[self.color], (self.x + j, self.y + i, 1, 1), 0)
def create_grid(locked_pos={}):
grid = [[0 for x in range(10)] for y in range(20)]
for i in range(len(grid)):
for j in range(len(grid[i])):
if (j, i) in locked_pos:
grid[i][j] = locked_pos[(j, i)]
return grid
def check_valid_position(shape, grid, pos):
for i in range(len(shape)):
for j in range(len(shape[i])):
if shape[i][j] > 0:
if not (0 <= pos[0] + j < len(grid[0]) and 0 <= pos[1] + i < len(grid)):
return False
if grid[pos[1] + i][pos[0] + j] > 0:
return False
return True
def get_shape():
return Block(5, 0, random.choice(shapes))
def main():
pygame.init()
width = 500
height = 700
screen = pygame.display.set_mode((width, height))
pygame.display.set_caption('Tetris')
clock = pygame.time.Clock()
fall_time = 0
fall_speed = 0.27
current_block = get_shape()
next_block = get_shape()
grid = create_grid()
game_over = False
while not game_over:
fall_time += clock.get_rawtime()
clock.tick()
if fall_time / 1000 >= fall_speed:
fall_time = 0
current_block.y += 1
if not check_valid_position(current_block.shape, grid, (current_block.x, current_block.y)):
current_block.y -= 1
for i in range(len(current_block.shape)):
for j in range(len(current_block.shape[i])):
if current_block.shape[i][j] > 0:
grid[current_block.y + i][current_block.x + j] = current_block.color
current_block = next_block
next_block = get_shape()
for event in pygame.event.get():
if event.type == pygame.QUIT:
game_over = True
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_LEFT:
current_block.move(-1)
if not check_valid_position(current_block.shape, grid, (current_block.x, current_block.y)):
current_block.move(1)
elif event.key == pygame.K_RIGHT:
current_block.move(1)
if not check_valid_position(current_block.shape, grid, (current_block.x, current_block.y)):
current_block.move(-1)
elif event.key == pygame.K_DOWN:
current_block.y += 1
if not check_valid_position(current_block.shape, grid, (current_block.x, current_block.y)):
current_block.y -= 1
elif event.key == pygame.K_UP:
current_block.rotate()
if not check_valid_position(current_block.shape, grid, (current_block.x, current_block.y)):
current_block.rotate()
screen.fill((0, 0, 0))
pygame.font.init()
font = pygame.font.SysFont('comicsans', 60)
label_score = font.render('Score: ', 1, (255, 255, 255))
screen.blit(label_score, (width - 200, height - 100))
for i in range(len(grid)):
for j in range(len(grid[i])):
pygame.draw.rect(screen, colors[grid[i][j]], (j * 30, i * 30, 30, 30), 0)
current_block.draw(screen)
next_block.draw(screen)
pygame.display.update()
pygame.quit()
if __name__ == '__main__':
main()
```
这只是一个基于Python语言的简单示例,其他编程语言中的实现方式可能会有所不同。
阅读全文