c++语音求裴波那契数列前40项
时间: 2023-08-01 21:13:11 浏览: 111
好的,以下是C++代码实现裴波那契数列前40项的程序:
```c++
#include <iostream>
using namespace std;
int main()
{
int fib[40];
fib[0] = 0;
fib[1] = 1;
for (int i = 2; i < 40; i++)
{
fib[i] = fib[i-1] + fib[i-2];
}
for (int i = 0; i < 40; i++)
{
cout << fib[i] << " ";
}
cout << endl;
return 0;
}
```
输出结果为:
0 1 1 2 3 5 8 13 21 34 55 89 144 233 377 610 987 1597 2584 4181 6765 10946 17711 28657 46368 75025 121393 196418 317811 514229 832040 1346269 2178309 3524578 5702887 9227465 14930352 24157817 39088169 63245986
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