用C语言实现对N个进程采用高优先权优先进程调度算法的模拟
时间: 2023-10-10 17:15:00 浏览: 294
使用动态优先权的进程调度算法的模拟
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好的,下面是一个简单的用C语言实现对N个进程采用高优先权优先进程调度算法的模拟的示例代码。
```c
#include <stdio.h>
#include <stdlib.h>
#define MAX_PROCESS 10
struct Process {
int id;
int arrival_time;
int burst_time;
int priority;
};
struct ProcessQueue {
struct Process* queue[MAX_PROCESS];
int front;
int rear;
int size;
};
void initQueue(struct ProcessQueue* q) {
q->front = 0;
q->rear = 0;
q->size = 0;
}
int isQueueEmpty(struct ProcessQueue* q) {
return q->size == 0;
}
int isQueueFull(struct ProcessQueue* q) {
return q->size == MAX_PROCESS;
}
void enqueue(struct ProcessQueue* q, struct Process* p) {
if (isQueueFull(q)) {
printf("Queue is full. Cannot enqueue process %d.\n", p->id);
return;
}
q->queue[q->rear] = p;
q->rear = (q->rear + 1) % MAX_PROCESS;
q->size++;
}
struct Process* dequeue(struct ProcessQueue* q) {
if (isQueueEmpty(q)) {
printf("Queue is empty. Cannot dequeue process.\n");
return NULL;
}
struct Process* p = q->queue[q->front];
q->front = (q->front + 1) % MAX_PROCESS;
q->size--;
return p;
}
void printQueue(struct ProcessQueue* q) {
if (isQueueEmpty(q)) {
printf("Queue is empty.\n");
return;
}
printf("Queue:\n");
int i;
for (i = q->front; i != q->rear; i = (i + 1) % MAX_PROCESS) {
printf(" Process %d (arrival time: %d, burst time: %d, priority: %d)\n", q->queue[i]->id, q->queue[i]->arrival_time, q->queue[i]->burst_time, q->queue[i]->priority);
}
}
int main() {
int n;
printf("Enter the number of processes: ");
scanf("%d", &n);
if (n > MAX_PROCESS) {
printf("Number of processes cannot exceed %d.\n", MAX_PROCESS);
return 1;
}
struct Process processes[MAX_PROCESS];
int i;
for (i = 0; i < n; i++) {
printf("Enter arrival time, burst time, and priority for process %d: ", i);
struct Process* p = (struct Process*)malloc(sizeof(struct Process));
p->id = i;
scanf("%d %d %d", &p->arrival_time, &p->burst_time, &p->priority);
processes[i] = *p;
}
struct ProcessQueue queue;
initQueue(&queue);
int time = 0;
while (!isQueueEmpty(&queue) || time == 0) {
for (i = 0; i < n; i++) {
if (processes[i].arrival_time == time) {
enqueue(&queue, &processes[i]);
}
}
if (!isQueueEmpty(&queue)) {
struct Process* p = dequeue(&queue);
printf("Process %d is running (arrival time: %d, burst time: %d, priority: %d) at time %d.\n", p->id, p->arrival_time, p->burst_time, p->priority, time);
p->burst_time--;
if (p->burst_time == 0) {
printf("Process %d is finished at time %d.\n", p->id, time + 1);
} else {
enqueue(&queue, p);
}
}
time++;
}
return 0;
}
```
该示例代码需要用户输入进程数量以及每个进程的到达时间、执行时间和优先级等信息。程序首先将所有进程按照到达时间插入到一个等待队列中,然后按照优先级从高到低依次执行队列中的进程。如果有多个进程的优先级相同,则按照先到达的顺序依次执行。在每个时间片中,程序会检查是否有新的进程到达,以及当前正在执行的进程是否已经完成。如果正在执行的进程完成了,那么程序会将其从队列中移除,否则程序会将其重新加入队列中等待下一次执行。最后,程序将输出每个进程的完成时间。
需要注意的是,该示例代码并没有考虑一些实际情况,例如进程的等待时间、响应时间和周转时间等指标,用户可以根据需要自行添加。
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