try expect finally执行顺序

以下是Java代码：

import java.util.*;

class Employee {
    private int id;
    private String name;
    private double salary;

    public Employee(int id, String name, double salary) {
        this.id = id;
        this.name = name;
        this.salary = salary;
    }

    public int getId() {
        return id;
    }

    public String getName() {
        return name;
    }

    public double getSalary() {
        return salary;
    }

    public String toString() {
        return "Employee{id=" + id + ", name='" + name + "', salary=" + salary + "}";
    }
}

public class Main {
    public static void main(String[] args) {
        Map<Integer, Employee> map = new HashMap<>();
        map.put(1001, new Employee(1001, "John", 50000.0));
        map.put(1002, new Employee(1002, "Jane", 60000.0));
        map.put(1003, new Employee(1003, "Bob", 70000.0));

        // 使用 keySet() 遍历 Map
        System.out.println("使用 keySet() 遍历 Map:");
        Set<Integer> keySet = map.keySet();
        for (int key : keySet) {
            Employee emp = map.get(key);
            System.out.println(key + " -> " + emp);
        }

        // 使用 entrySet() 遍历 Map
        System.out.println("使用 entrySet() 遍历 Map:");
        Set<Map.Entry<Integer, Employee>> entrySet = map.entrySet();
        for (Map.Entry<Integer, Employee> entry : entrySet) {
            int key = entry.getKey();
            Employee emp = entry.getValue();
            System.out.println(key + " -> " + emp);
        }
    }
}

输出结果：

使用 keySet() 遍历 Map:
1001 -> Employee{id=1001, name='John', salary=50000.0}
1002 -> Employee{id=1002, name='Jane', salary=60000.0}
1003 -> Employee{id=1003, name='Bob', salary=70000.0}
使用 entrySet() 遍历 Map:
1001 -> Employee{id=1001, name='John', salary=50000.0}
1002 -> Employee{id=1002, name='Jane', salary=60000.0}
1003 -> Employee{id=1003, name='Bob', salary=70000.0}