5人抢答器verilog
时间: 2024-05-07 11:20:42 浏览: 63
以下是一个简单的 5 人抢答器的 Verilog 代码示例:
```verilog
module quiz_buzzer (
input clk,
input rst,
input [4:0] buzzer_in,
output [4:0] buzzer_out,
output reg interrupt
);
// 内部计数器
reg [2:0] count;
// 内部 buzzer 计数器
reg [2:0] buzzer_count;
// buzzer 计数器是否使能
reg buzzer_enable;
// 五个 buzzer 的状态
reg [4:0] buzzer_status;
always @(posedge clk) begin
if (rst) begin
count <= 0;
buzzer_count <= 0;
buzzer_enable <= 0;
buzzer_status <= 0;
interrupt <= 0;
end
else begin
// 计数器自增
count <= count + 1;
// 每隔 5 个时钟周期切换 buzzer
if (count == 5) begin
count <= 0;
if (buzzer_enable) begin
// 切换当前 buzzer 状态
buzzer_status[buzzer_in] <= ~buzzer_status[buzzer_in];
// 如果所有 buzzer 都已被触发,则触发中断
if (&buzzer_status == 1) begin
interrupt <= 1;
end
end
end
// 每隔 100 个时钟周期切换 buzzer 计数器
if (count % 100 == 0) begin
buzzer_count <= buzzer_count + 1;
if (buzzer_count == 5) begin
buzzer_count <= 0;
buzzer_enable <= 1;
end
end
end
end
assign buzzer_out = buzzer_status;
endmodule
```
该代码模拟了一个 5 人抢答器系统,其中每 100 个时钟周期会切换到下一个 buzzer,每 5 个时钟周期会切换当前 buzzer 的状态。如果所有 buzzer 都已被触发,则会触发中断信号。
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