SELECT room.roomtype, inhotel.innum, worker.workname FROM room JOIN inhotel ON inhotel.roomnum = room.roomnum JOIN (SELECT workname, worknum FROM worker) AS w ON inhotel.worknum = w.worknumJOIN worker ON w.workname = worker.workname; ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'worker ON w.workname = worker.workname' at line 1

根据你提供的 SQL 语句，错误提示是在第一行末尾缺少了一个空格，导致后面的 JOIN 子句被误认为是一部分的第一行语句。应该在第一行的末尾添加一个空格，修改后的 SQL 语句如下：

SELECT room.roomtype, inhotel.innum, worker.workname 
FROM room 
JOIN inhotel ON inhotel.roomnum = room.roomnum 
JOIN (SELECT workname, worknum FROM worker) AS w ON inhotel.worknum = w.worknum 
JOIN worker ON w.workname = worker.workname;

这样应该可以解决问题。

相关问题

select room.roomtype,inhotel.innum,worker.worker.workname from room -> join inhotel on inhotel.roomnum=room.roomnum -> join(select workname,worknum from worker)workname on inhotel.worknum=workname.worknum -> join worker on workname.workname=worker.worknamr; ERROR 1054 (42S22): Unknown column 'worker.worker.workname' in 'field list'

根据你提供的 SQL 语句，出现了两个错误：

1. 在第一行中，应该将 "worker.worker.workname" 修改为 "worker.workname"。
2. 在第三行中，应该将 "workname.workname" 修改为 "workname"。

修改后的 SQL 语句如下：

SELECT room.roomtype, inhotel.innum, worker.workname 
FROM room 
JOIN inhotel ON inhotel.roomnum = room.roomnum 
JOIN (SELECT workname, worknum FROM worker) AS workname ON inhotel.worknum = workname.worknum 
JOIN worker ON workname.workname = worker.workname;

这样应该可以解决问题。

select room.roomtype,inhotel.innum,worker.workname from room -> join inhotel on inhotel.roomnum=room.roomnum join (select workname from worker)workname on inhotel.worknum=worker.worknum; ERROR 1054 (42S22): Unknown column 'worker.workname' in 'field list'

根据你提供的 SQL 语句，错误提示是无法识别 "worker.workname" 这个列名，这是因为你在子查询中创建了一个名为 "workname" 的子查询表，但你没有给它一个别名，所以在主查询中无法引用它。

可以尝试修改 SQL 语句，给子查询表 "workname" 添加一个别名，例如：

SELECT room.roomtype, inhotel.innum, w.workname 
FROM room 
JOIN inhotel ON inhotel.roomnum = room.roomnum 
JOIN (SELECT workname FROM worker) AS w ON inhotel.worknum = w.worknum;

这样应该可以解决问题。