def __check_cmd(self): byte4 = 0 for i in range(32): x = i * 2 t = self.buf64[x] + self.buf64[x+1] byte4 <<= 1 if t >= 1800 and t <= 2800: byte4 += 1 user_code_hi = (byte4 & 0xff000000) >> 24 user_code_lo = (byte4 & 0x00ff0000) >> 16 data_code = (byte4 & 0x0000ff00) >> 8 data_code_r = byte4 & 0x000000ff self.cmd = data_code
时间: 2023-02-07 09:24:45 浏览: 78
这段代码看起来是在检查一个命令。它似乎正在遍历一个长度为32的列表 "self.buf64",并且在每次遍历时将一个数字 "t" 与 1800 和 2800 进行比较。如果 "t" 大于等于1800 并且小于等于2800,那么将变量 "byte4" 左移一位并将其设置为 1。最后,它似乎在将变量 "user_code_hi" 设置为 "byte4"。
相关问题
请在(1)处填上合适的代码。 class seq: n=0 def (1)(self): self.n+=1 return self.n def __iter__(self): return self if __name__=='__main__': s=seq() for i in range(5): print(next(s),end=' ')
请在(1)处填上合适的代码:
```
def __next__(self):
return self.n
```
完整代码如下:
```
class seq:
n=0
def __next__(self):
self.n+=1
return self.n
def __iter__(self):
return self
if __name__=='__main__':
s=seq()
for i in range(5):
print(next(s),end=' ')
```
输出结果为:1 2 3 4 5
def check(i,j): t=[0]*5 for x in range(4): t[d[i][x]]=1 #检查同一行 t[d[x][j]]=1 #检查同一列 #检查对角线 if i<=1 and j<=1: t[d[1-i][1-j]]=1 elif i<=1 and j>=2: t[d[1-i][5-j]]=1 elif i>=2 and j<=1: t[d[5-i][1-j]]=1 elif i>=2 and j>=2: t[d[5-i][5-j]]=1 k=0 for a in range(1,5): if t[a]==0: __________ else: k+=1 if __________: return n else: return 0 d=[[0 for j in range(4) ] for i in range(4) ] for i in range(4): d[i]=list(map(int,input().split(","))) flag=False while __________: flag=True for i in range(4): for j in range(4): if d[i][j]==0: d[i][j]=check(i,j) if __________: flag=False for i in range(4): for j in range(4): print(d[i][j],end=" ") print(" ")
缺失的代码应该是:
```python
if k == 4:
return n
else:
return 0
```
```python
while flag:
flag = False
for i in range(4):
for j in range(4):
if d[i][j] == 0:
d[i][j] = check(i, j)
if d[i][j] != 0:
flag = True
```
完整的代码如下:
```python
def check(i, j):
t = [0] * 5
for x in range(4):
t[d[i][x]] = 1 #检查同一行
t[d[x][j]] = 1 #检查同一列
#检查对角线
if i <= 1 and j <= 1:
t[d[1 - i][1 - j]] = 1
elif i <= 1 and j >= 2:
t[d[1 - i][5 - j]] = 1
elif i >= 2 and j <= 1:
t[d[5 - i][1 - j]] = 1
elif i >= 2 and j >= 2:
t[d[5 - i][5 - j]] = 1
k = 0
for a in range(1, 5):
if t[a] == 0:
k += 1
if k == 4:
return n
else:
return 0
d = [[0 for j in range(4)] for i in range(4)]
for i in range(4):
d[i] = list(map(int, input().split(",")))
flag = False
while flag:
flag = False
for i in range(4):
for j in range(4):
if d[i][j] == 0:
d[i][j] = check(i, j)
if d[i][j] != 0:
flag = True
for i in range(4):
for j in range(4):
print(d[i][j], end=" ")
print(" ")
```
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